Answer:
That unknown substance is water
Explanation:
Answer:
<u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.
Correct answer - C
Explanation:
A solid sodium metal reacts with gaseous form of chlorine gas to form a solid sodium chloride.
This formation of sodium chloride arises due to transfer of one valence electron from sodium to chlorine atom and the both atoms get stable octet electronic configuration.
As a result, an ionic compound solid sodium chloride is formed.
The chemical reaction of formation sodium chloride is as follows.

Therefore, <u>only sodium chloride compounds</u> MOST LIKELY products of the reaction between sodium metal and chlorine gas.
Answer:
a) is the answer as water directly changes its state
Answer:
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The question is incomplete, the complete question is;
Using the following equation 2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq) how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid
Answer:
355.1 g
Explanation:
The equation of the reaction is;
2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq)
We have been told that H2SO4 is in excess so NaOH is the limiting reactant. Therefore;
Number of moles in 200g of NaOH = 200g/40g/mol = 5 moles
So;
2 moles of NaOH yields 1 mole of Na2SO4
5 moles of NaOH will yield 5 * 1/2 = 2.5 moles of Na2SO4
Molar mass of Na2SO4 = 142.04 g/mol
Mass of Na2SO4= 2.5 moles * 142.04 g/mol = 355.1 g