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olasank [31]
4 years ago
10

A sample of pure gold has a mass of 10.2 g. Calculate the number of moles in the sample and gold atoms in the sample.

Chemistry
1 answer:
Karo-lina-s [1.5K]4 years ago
4 0

Answer:

Explanation:

molecular weight of gold = 197

converting 10.2 g into moles

no of moles = 10.2 / 197

= .0518 moles

one  mole of any element contains 6.02 x 10²³ number of atoms

.0518 moles will contain 6.02 x .0518 x 10²³ atoms of gold

= .311 x 10²³ no of atoms of gold .

= 3.11 x 10²² no of atoms of gold

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Answer:

Explanation:

We know that

pH +pOH = 14

Given pH = 8.30

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7 0
3 years ago
Calculate the osmotic pressure of a magnesium citrate laxative solution containing 25.5 g of magnesium citrate in 244 mL of solu
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Answer:

The answer to your question is π = 12.47 atm

Explanation:

Data

mass of Magnesium citrate = 25.5 g

volume of solution = 244 ml

temperature = 37°C

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Process

1.- Calculate the moles of magnesium citrate

                         214 grams ----------------- 1 mol

                          25.5 grams ---------------  x

                           x = (25.5 x 1)/214

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2.- Calculate molarity

Molarity = moles/volume

Molarity = 0.119/0.244

Molarity = 0.49

3.- Calculate osmotic pressure

π = MRT

π = (0.49)(0.0821)(37 + 273)

π = (0.49)(0.0821)(310)

π = 12.47 atm

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