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yan [13]
3 years ago
9

Where are the alkali metals and the halogens located on the periodic table?

Chemistry
1 answer:
Setler79 [48]3 years ago
3 0
Alkali: Group 1(I A). Halogens: group 17 (VII A)
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What does the fossil record document?
slava [35]

Answer:

The collection of fossils and their placement in chronological order is known as the fossil record

I think??

6 0
3 years ago
HeLP PLeaSe SEND HElP AAAAAAAAAAAAA
nevsk [136]

Answer:

Correct answer is Li

Explanation:

Lithium reacts with chlorine to form Lithium chloride.

$2Li+Cl_{2} \to 2LiCl$

This is a redox (Oxidation -Reduction) reaction

$2Li^{0} \to 2Li^{+2}+2e^{-}$ - Oxidation$Cl_{2}^{0}+2e^{-} \to 2Cl^{-}$  - Reduction

Hence the reducing agent in this reaction is Li

4 0
4 years ago
Read 2 more answers
1. Which liquid sample is a pure substance?
IRISSAK [1]

The whole Activity , poem and paragraph is missing in the question.

Answer:

(1) Liquid A

(2) Solid A

Explanation:

Using this part of the given poem

Substances and mixtures behave differently,

During boiling and melting most especially

Boiling point of substance is fixed while mixture is not

Substance melts completely but mixture does not

The boiling point of the Pure substance remain fixed after reaching its boiling point this is shown by Liquid A

Solid A is melting completely so Solid A is a pure substance.

6 0
3 years ago
If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?
kolezko [41]

Answer:

  • <u>3.0M</u>

Explanation:

The dilution formula is:

       M_1\times V_1=M_2\times V_2

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

  • M₁ = <em>6.0M</em>
  • M₂ = unknown
  • V₁ = <em>251 mL</em>
  • V₂ = <em>500. mL</em>

         6.0M\times 251ml=M_2\times 500.ml

Clear M₂ and compute:

         M_2=6.0M\times 251ml/500.ml\approx3.0M

8 0
3 years ago
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. this result indicates
LuckyWell [14K]
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. This result of the experiment indicates that most of the volume of a gold atom consists of unoccupied spaces. This was an experiment done by Ernest Rutherford which allowed him to verify the presence of the a small region positive charge in an atom which is called as the nucleus of the atom. Most of the alpha particles pass through the foil while a certain amount were deflected. Those that pass through confirmed that there is a large area that is unoccupied in an atom.
8 0
4 years ago
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