Moles =CaCo3=20g/100 gm/mol=0.2
Answer is: <span>the approximate molar mass of a molecular solute is 150 g.
</span>m(molecular solute) = 300 g.
m(water) = 1000 g ÷ 1000 g/kg = 1 kg.
ΔT = 101°C - 100°C = 1°C.
M(molecular solute) = Kb · m(molecular solute) / m(water) · ΔT.
M(molecular solute) = 0,512°C/m · 300 g / (1 kg · 1°C).
M(molecular solute) = 153,6 g/mol.
Answer:
9.62 μm
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 31.2 THz
Wavelength (λ) =..?
Next, we shall convert 31.2 THz to Hz.
This can be obtained as follow:
Recall:
1 THz = 1×10¹² Hz
Therefore,
31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz
31.2 THz = 3.12×10¹³ Hz
Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.
Finally, we shall determine the wavelength (λ) infrared radiation as follow:
Frequency (f) = 3.12×10¹³ Hz.
Velocity (v) = 3×10⁸ m/s
Wavelength (λ) =..?
V = λf
3×10⁸ = λ × 3.12×10¹³
Divide both side by 3.12×10¹³
λ = 3×10⁸ / 3.12×10¹³
λ = 9.62×10¯⁶ m
Converting 9.62×10¯⁶ m to micro metre (μm) we have:
1 m = 1×10⁶ μm
Therefore,
9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m
9.62×10¯⁶ m = 9.62 μm
Therefore, the wavelength of the infrared radiation is 9.62 μm
Explanation:
Formula according to the radius ratio rule is as follows.
= 0.397
According to the radius ratio rule, as the calculated value is 0.397 and it lies in between 0.225 to 0.414. Therefore, it means that the type of void is tetrahedral.
Thus, we can conclude that the given compound is most likely to adopt closest-packed array with lithium ions occupying tetrahedral holes.
1 molecule of glutamate can form 7.6 ATP can be formed by oxidative phosphorylation .
<h3>
What is oxidative Phosphorylation ?</h3>
In the process of oxidative phosphorylation, oxygen is consumed as electrons are transferred through the mitochondrial electron transport chain and ATP is produced.
The bulk of the ATP required for higher animals and plants to sustain life is produced by oxidative phosphorylation, which is also in charge of creating and preserving metabolic equilibrium.
The glutamate carrier recycles glutamate outside of mitochondria (T9). One aspartate and 7.6 ATP are made at the best return for each glutamine.
To learn more about oxidative phosphorylation, refer to the below link:
brainly.com/question/25765324
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