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Misha Larkins [42]
3 years ago
7

If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?

Chemistry
1 answer:
kolezko [41]3 years ago
8 0

Answer:

  • <u>3.0M</u>

Explanation:

The dilution formula is:

       M_1\times V_1=M_2\times V_2

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

  • M₁ = <em>6.0M</em>
  • M₂ = unknown
  • V₁ = <em>251 mL</em>
  • V₂ = <em>500. mL</em>

         6.0M\times 251ml=M_2\times 500.ml

Clear M₂ and compute:

         M_2=6.0M\times 251ml/500.ml\approx3.0M

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Answer:

Molarity = 0.002 M

Explanation:

Given data:

Mass of calcium chloride = 0.321 g

Volume of water = 1.45 L

Molarity of solution = ?

Solution:

Molarity = number of moles / volume in litter.

We will calculate the number of moles of calcium chloride first.

Number of moles = mass/molar mass

Number of moles = 0.321 g/ 110.98 g/mol

Number of moles = 0.003 mol

Molarity:

Molarity = 0.003 mol / 1.45 L

Molarity = 0.002 M

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For the reaction, X + Y → A + B, ΔGo is –1324 kJ. Which one of the following statements is NOT valid concerning the reaction?
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c. The reaction will proceed rapidly from left to right.

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Earth is about 150 million km from the Sun. The radiation coming from the Sun travels at 300,000 km/s. How long does it take for
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A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How
IrinaK [193]

Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 783J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 254 g

\Delta T = change in temperature = T_2-T_1=(23.73-26.01)=-2.28^oC

Now put all the given values in the above formula, we get:

q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]

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Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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