Question

If 251 mL of 6.0 M H2SO4 is diluted to 500. mL, what is its new molarity?

Answer 1

Answer:

• 3.0M

Explanation:

The dilution formula is:

       $M_1\times V_1=M_2\times V_2$

Where M₁ and M₂ are the molar concentrations and V₁ and V₂ are the volumes of the concentrated and the diluted solutions.

Substitute:

• M₁ = 6.0M

• M₂ = unknown

• V₁ = 251 mL

• V₂ = 500. mL

         $6.0M\times 251ml=M_2\times 500.ml$

Clear M₂ and compute:

         $M_2=6.0M\times 251ml/500.ml\approx3.0M$