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Advocard [28]
4 years ago
14

In a double replacement reaction resulting in the formation of solid calcium carbonate, the resulting supernatant would be descr

ibed as __________.
a) saturated with CaCO3
b) containing no ions of CaCO3
c) supersaturated with CaCO3
d) unsaturated with CaCO3
I know it's a, but I don't understand why.
Chemistry
1 answer:
Nana76 [90]4 years ago
8 0

a) saturated with CaCO3, because when maximum solute gets dissolve to form precipitate as when solute is saturated with solvent and then precipitates hence the supernatant is saturated with CaCO3.

Explanation:

In double displacement reaction two ionizable compounds exchange their cation or anion forming an insoluble compound that is precipitate. The supernatant will be the solvent and dissolved solute.

We know that precipitation is formed when solubility of the compound exceeds to that of other.

The solubility occurs when it exceeds the saturation in the solution.

So, the precipitate has overcome the saturation in solvent, the resulting supernatant is saturated with CaCO3 or the solute.

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After a group of researchers conducts a new experiment that has never been conducted before, what is the best way for other scie
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Answer:

Attempt to replicate the experiment

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3 years ago
Given the balanced equation representing a reaction: HCl + H₂O → H₃O⁺ + Cl⁻ The water molecule acts as a base because it
Wittaler [7]

Answer:

accepts an H⁺

Explanation:

The following balanced ionic equation is given in this question;

HCl + H₂O → H₃O⁺ + Cl⁻

According to Brønsted–Lowry acid–base theory, a base is any substance that can accept hydrogen ions or protons (H+). Using this definition for the above equation, water (H2O) accepts a proton or H+ that was donated by HCl to form H30+ (hydronium ion), hence, water is acting as a BASE in this reaction because it accepts an H+.

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3 years ago
Zeros that act as are not significant
GaryK [48]

Explanation:

non zeores digits always significant any zero between two significant digits are significant a final zeros in the decimal portion only are significant

6 0
3 years ago
What pressure would have to be applied to steam at 315°c to condense the steam to liquid water (δh vap = 40.7 kj/mol)?
sladkih [1.3K]
1 answer · Chemistry 

 Best Answer

Water steam condenses if its pressure is equal to vapor saturation vapor pressure. 

Use the Clausius-Clapeyron relation. 
I states the temperature gradient of the saturation pressure is equal to the quotient of molar enthalpy of phase change divided by molar volume change due to phase transition time temperature: 
dp/dT = ΔH / (T·ΔV) 
Because liquid volume is small compared to vapor volume 
ΔV in vaporization is approximately equal to to the vapor volume. Further assume ideal gas phase: 
ΔV ≈ V_v = R·T/p 
Hence 
dp/dT = ΔHv / (R·T²/p) 
<=> 
dlnp/dT = ΔHv / (R·T²) 

If you solve this DE an apply boundary condition p(T₀)= p₀. 
you get the common form: 
ln(p/p₀) = (ΔHv/R)·(1/T₀ - 1/T) 
<=> 
p = p₀·exp{(ΔHv/R)·(1/T₀ - 1/T)} 

For this problem use normal boiling point of water as reference point: 
T₀ =100°C = 373.15K and p₀ = 1atm 
Therefore the saturation vapor pressure at 
T = 350°C = 623.15K 
is 
p = 1atm ·exp{(40700J / 8.314472kJ/mol)·(1/373.15K - 1/623.15K)} = 193 atm 
hope this helps
3 0
4 years ago
The amount of heat absorbed by the alcohol was determined to be 1.17kJ. Given that the specific heat of the alcohol is 2.42J/gC
quester [9]

Answer:

                      ΔT  =  20.06 °C

Explanation:

The equation used for this problem is as follow,

                                    Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  1.17 kJ = 1170 J

           m  =  mass  =  24.1 g

           Cp  =  Specific Heat Capacity  =  2.42 J.g⁻¹.°C⁻¹

           ΔT  =  Change in Temperature  =  <u>??</u>

Solving eq. 1 for ΔT,

                                ΔT  =  Q / m Cp

Putting values,

                                ΔT  =  1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹

                                ΔT  =  20.06 °C

6 0
3 years ago
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