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Vikki [24]
3 years ago
6

How many aluminum atoms are in 2.58 grams of aluminum

Chemistry
1 answer:
Ket [755]3 years ago
6 0

Answer:

5.75x10^22 atoms

Explanation:

From a clear understanding of Avogadro's hypothesis, we discovered that 1mole of any substance contains 6.02x10^23 atoms. This implies that 1mole of Al also contains 6.02x10^23 atoms.

1mole of Al = 27g

If 27g of Al contains 6.02x10^23 atoms, then 2.58g of Al will contain = (2.58 x 6.02x10^23)/27 = 5.75x10^22 atoms

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Answer:

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Explanation:

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3 years ago
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Answer: fourth option, 10.8 kJ


Explanation:


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