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Nataliya [291]
3 years ago
6

How would you separate copper sulfate crystals from its solution?​

Chemistry
1 answer:
tia_tia [17]3 years ago
4 0

Answer: You would separate it by dissolving them.

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How can room things in a house save energy? List at least 5 ways in which you can save heat energy. Explain how each one can sav
pychu [463]

Answer:

brainly

Explanation:

Adjust your day-to-day behaviors.

Replace your light bulbs.

Use smart power strips.

Install a programmable or smart thermostat.

Purchase energy efficient appliances.

3 0
2 years ago
A train in Japan can travel 813.5 miles in 5 hours
Anastaziya [24]

Answer:

162.7miles/hr

Explanation:

Given parameters:

Distance covered by the train  = 813.5miles

Time taken  = 5hours

Unknown:

Speed of the train  = ?

Solution:

Speed is a physical quantity.

It is mathematically expressed as;

      Speed  = \frac{distance}{time}

So, input parameters and solve;

   Speed  = \frac{813.5}{5}  = 162.7miles/hr

8 0
3 years ago
What is the formula for CO3 2- and Al3+ ?
Goryan [66]

Answer is: formula is Al₂(CO₃)₃.

Aluminium carbonate (Al₂(CO₃)₃) has neutral charge. Because aluminium cation has positive charge 3+ and carbonate anion has negative charge 2-, for right chemical formula, we need two aluminium cations and three carbonate anion:

charge of the molecule = 2 · (3+) + 3 · (-2).

charge of the molecule = 0.

7 0
3 years ago
Read 2 more answers
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
A chemist must prepare of 800.0 ml potassium hydroxide solution with a pH of 13.00 at 25°.
ArbitrLikvidat [17]

Answer:

4.48 grams is the mass of potassium hydroxide that the chemist must weigh out in the second step.

Explanation:

The pH of the solution = 13.00

pH + pOH = 14

pOH = 14 - pH = 14 - 13.00 = 1.00

pOH=-\log[OH^-]

1.00=-\log[OH^-]

[OH^-]=10^{-1.00} M=0.100 M

KOH(aq)\rightarrow K^+(aq)+OH^-(aq)

[KOH]=[OH^-]=[K^+]=0.100 M

Molariy of the KOH = 0.100 M

Volume of the KOH solution = 800 mL= 0.800 L

1 mL = 0.001 L

Moles of KOH = n

Molarity=\frac{Moles}{Volume(L)}

0.100 M=\frac{n}{0.800 L}

n = 0.0800 mol

Mass of 0.0800 moles of KOH :

0.0800 mol × 56 g/mol = 4.48 g

4.48 grams is the mass of potassium hydroxide that the chemist must weigh out in the second step.

4 0
3 years ago
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