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ratelena [41]
3 years ago
13

Please help will reward brainliest

Chemistry
1 answer:
Reil [10]3 years ago
3 0
To decrease the temperature of the ice bath
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How much energy does a 445 nm wave of light have? (The speed of light in a
Dahasolnce [82]

Answer:

A

Explanation:

To calculate questions like this, you need to make use of the equation below:

E = hν

E is the energy, h is Planck's constant, and ν is the frequency.

Also, another important formula you need for this question is the following:

ν = c / λ

ν is the frequency, c is the speed of light, and λ is the wavelength.

Therefore, E = hν = hc/λ.

Also remember to convert nm wavelength to meters.

To answer the question, E = hc/λ = ((6.626*10^-34 J•s)(3*10^8 m/s))/(4.45*10-7 m) = 4.42 • 10^-19 J = A

8 0
2 years ago
What would you have to do to the substance in
jenyasd209 [6]
By using thermal energy which is also heat energy the substance in cup A will melt becoming a liquid behaving like the substance in cup B
5 0
2 years ago
When would a cell use Active Transport? Mark all that apply.
Westkost [7]

Answer:

a c e

Explanation:

4 0
3 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
The atomic number is always equal to the atomic mass true false
kifflom [539]

Answer:

<h3>A neutral (no charge) particle found in the nucleus of an atom. ... The atomic number of an atom is equal to the number of protons or neutrons? false. The atomic number is always equal to the atomic mass.</h3>
7 0
3 years ago
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