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yulyashka [42]
3 years ago
10

I need help this one:(( please help me

Chemistry
1 answer:
agasfer [191]3 years ago
8 0
The answer is D because inherited is in the genes and enviornment is what happens around you
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In the following reaction, what is the quantity of heat (in kJ) released when 5.87 moles of CH₄ are burned?
IRISSAK [1]

Taking into account the definition of enthalpy of a chemical reaction, the quantity of heat released when 5.87 moles of CH₄ are burned is 4,707.74 kJ.

The enthalpy of a chemical reaction as the heat absorbed or released in a chemical reaction when it occurs at constant pressure. That is, the heat of reaction is the energy that is released or absorbed when chemicals are transformed into a chemical reaction.

The enthalpy is an extensive property, that is, it depends on the amount of matter present.

In this case, the balanced reaction is:

CH₄ (g) + 2 O₂ (g) → CO₂ (g) + 2 H₂O(g)

and the enthalpy reaction ∆H° has a value of -802 kJ/mol.

This equation indicates that when 1 mole of CH₄ reacts with 2 moles of O2, 802 kJ of heat is released.

When 5.87 moles of CH₄ are burned, then you can apply the following rule of three: if 1 mole of CH₄ releases 802 kJ of heat, 5.87 moles of CH₄ releases how much heat?

heat=\frac{5.87 molesof CH_{4}x802 kJ}{1 mol of CH_{4} }

<u><em>heat= 4,707.74 kJ</em></u>

Finally, the quantity of heat released when 5.87 moles of CH₄ are burned is 4,707.74 kJ.

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5 0
2 years ago
How many grams are in 5 moles of 7.75 grams?
lesya692 [45]

Answer:

21

Explanation:

bcecause thats the only one

5 0
2 years ago
A certain drug has a half-life in the body of 4.0h. What should the interval between doses be, if the concentration of drug in t
scZoUnD [109]

Answer:

Explanation:

half life = 4 h

initial concentration = 100

final concentration = 15

Time = t

No of half life  x = t / 4

15 = 100 x ( 1/2 )ˣ

.15 =  ( 1/2 )ˣ

ln .15 = - x ln2

x = - ln .15 / ln 2

= 1.897 / .693

x = 2.737

x = t / 4

t = 2.737 x 4 = 11 h approx .

8 0
3 years ago
How much energy is needed to vaporize 75.0 g of diethyl ether (c4h10o) at its boiling point (34.6°c), given that δhvap of diethy
malfutka [58]

Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

Explanation:

First we have to calculate the moles of diethyl ether

\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles

As, 1 mole of diethyl ether require heat = 26.5 kJ

So, 1.01  moles of diethyl ether require heat = \frac{26.5}{1}\times 1.01=26.8kJ

Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

5 0
3 years ago
What is a spelling bee​
Lisa [10]

Answer: a contest in which you are eliminated if you fail to spell a word correctly.

8 0
3 years ago
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