Answer:
DM me I have an answer set up but it won't let me here because it's "too long" hope to here back from you! (sorry about this Brainly has been acting up on me lately!!!!!)
Explanation:
Answer:
Option B is not correct
Explanation:
Dialogues become problematic when they appear automatically because of high level incompatibility
Answer:
The correct pseudocode to find the records of all citizens over the age of 50 is IF(age > 50).
OR EACH item IN citzlist
{
WHILE(not end of citzlist)
{
IF(age > 50)
{
DISPLAY(name)
}
}
}
If this is run, it will bring out all the names of the citizen who are over the age of 50 in the list.
Explanation:
Answer:
class OddNumber
{
public static void main(String args[])
{
int n = 1000; //Store 1000 in Variable n typed integer
System.out.print("Odd Numbers from 1 to 1000 are:"); // Print headline of output window
for (int i = 1; i <= n; i++) //For loop to go through each number till end
{
if (i % 2 != 0) //check if number is even or odd.Not divisible by 2 without reminder means it is odd number
{
System.out.print(i + " "); //print odd numbers
}
}
}
}
