1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timama [110]
3 years ago
6

HELP PLZZZ!!!! Hurry

Physics
2 answers:
Mashcka [7]3 years ago
8 0

Answer:

3. When the number of turns, N is doubled, the strength of the electromagnet is also doubled

4. Doubling the voltage, doubles the strength of the electromagnet

5. The number of paper clips a 7.5 V battery would pick is approximately 28 paper clips

The number of paper clips a 7.5 V battery would pick is 59 paperclips

6. For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is approximately 7 paperclips

For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is 16 paperclips

Explanation:

3. The Magnetomotive Force, MMF = The Number of Turns on the Coil, N × The Current I Flowing in the Coil, I

∴ MMF = N × I

When the number of turns, N is doubled, the magnetomotive force, MMF is also doubled, and the strength of the electromagnet is doubled

4. Given that the voltage, V applied to the coil = The current, I flowing × The resistance, R of the coil, we have

V = I × R

Therefore, for a given constant resistance in the coil, doubling the voltage, doubles the current and therefore doubles the strength of the electromagnet

5. The average slope for the 25-coil electromagnet = (23 - 12)/(6 - 3) = 3.\bar 6

The number of paper clips a 7.5 V battery would pick = 12 + (7.5 - 3) × 11/3 = 28.5 paperclips  ≈ 28 paper clips

The average slope for the 50-coil electromagnet = (48 - 26)/(6 - 3) = 7.\bar 3

The number of paper clips a 7.5 V battery would pick = 26 + (7.5 - 3) × 22/3 = 59 paperclips

6. The slope calculated from a start point of approximately 0.4 V, is given as follows;

The slope for the 25-coil electromagnet = (12 - 6)/(3 - 0.4) = 30/13

Therefore, for the 25-coil electromagnet,  the average number of paper clips a 1 V battery would pick = 6 + (1 - 0.4) × 30/13) = 96/13 ≈ 7 paperclips

The slope for the 50-coil electromagnet = (26 - 13)/(3 - 0.4) = 5

Therefore, for the 50-coil electromagnet,  the average number of paper clips a 1 V battery would pick = 13 + (1 - 0.4) × 5 = 16 paperclips

gregori [183]3 years ago
6 0

Answer:

The person above is correct. sorry for not being able to give a better answer!

You might be interested in
When an 81.0-kg adult uses a spiral staircase to climb to the second floor of his house, his gravitational potential energy incr
kap26 [50]

Assuming both staircases are of equal height from the ground floor, then the nature of the staircase does not change the gravitational potential energy.


We can, from information given, find the height of the floor, and then apply to the child using the standard formula, E=mgh.


However, in this case, it is a matter of proportions, i.e.


81.0 kg : 2.25 kJ

17.5 kg : x kJ

cross multiply to get

x=2.25*17.5/81=0.486 kJ (or 486 J) to three significant figures.

3 0
3 years ago
If the image
Zina [86]

Answer:

The lens is a concave lens

Explanation:

In concave lens, the image formed is erect. diminished and virtual. The more the distance of the object from the mirror, the more diminished the image formed will be. Concave lens are used in binoculars and telescopes and are installed before or in the eye piece to enable a clear focus.

4 0
3 years ago
A simple pendulum consists of a 2 kg bob attached to a 1.5 m long string. How much time (in s) is required for this pendulum to
Charra [1.4K]

Answer:

6.15 s

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

For the pendulum in this problem,

L = 1.5 m (length)

g=9.8 m/s^2 (acceleration due to gravity on Earth)

Therefore, its period is

T=2\pi \sqrt{\frac{1.5}{9.8}}=2.46 s

And therefore, the time taken for the pendulum to complete 2.5 oscillations is equal to 2.5 times the period:

t=2.5T=(2.5)(2.46)=6.15 s

3 0
3 years ago
How much power does it take to lift 30.0 kg 100 m high in 5.00 s?
zheka24 [161]

._.Answer:.

ijji._. ji

Explanation:.

5 0
3 years ago
Two hockey players are skating toward each other on a frictionless ice. One is moving at 1 m/s while the other is traveling at 2
MAVERICK [17]

Their combined speed will be 1m/s

Given the following parameters;

  • The velocity of the first hockey player is 1m/s.
  • The velocity of the second hockey player is 2m/s.

If the player collides and stick together, the combined speed is expressed as;

  • Combined speed = differences in velocity
  • Combined speed = 2m/s - 1m/s
  • Combined speed = 1m/s.

Hence their combined speed will be 1m/s

Learn more on collision here: brainly.com/question/7538238

7 0
3 years ago
Other questions:
  • How do positive and negative acceleration differ
    14·1 answer
  • HELP PLEASE EASY MULTIPLE CHOICE!!! PPLLLLLLELEEEEEAAAASSSSSEEEE!!!!!
    6·2 answers
  • Assume that a uniform magnetic field is directed into the monitor you are reading this on. If an electron is released with an in
    7·1 answer
  • In a physics laboratory experiment, a coil with 200 turns enclosing an area of 12 cm2 is rotated in 0.040 s from a position wher
    9·1 answer
  • This is a line graph used to describe the motion of an object. A graphic representation of velocity. Also used to represent spee
    9·2 answers
  • Create a list of 5 potential jobs that students of genealogy can obtain.
    5·1 answer
  • What is the total net charge of an atom that contains 13 protons and 10 electrons? *
    8·1 answer
  • A ferry coming into port is sailing at 12 m/s. It takes 2.5km to come to rest in the port. Calculate the deceleration of the fer
    7·1 answer
  • What happens to the arrangement of atoms in matter as it is heated?
    14·2 answers
  • True or False: A sound wave causes particles of air to travel from the source of sound (e.g., the speaker) to the listener's ear
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!