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3 years ago

What are groups 1,2 and 3 examples of on the periodic table

1 answer:

4 0

The number of the group identifies the column of the standard periodic table in which the element appears.
Group 1 contains the alkali metals ( lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium(Fr).)
Group 2 contains the alkaline earth metals ( beryllium (Be),magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba) and radium (Ra) )
Group 3: Scandium (Sc) and yttrium (Y)

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A car of mass 500 kg is moving at a speed of 1.2 m/s. A man pushes the car,

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3 years ago

A typical running track is an oval with 74-mm-diameter half circles at each end. A runner going once around the track covers a d

lisabon 2012 [21]

The centripetal acceleration a is 4.32 $\times$ 10^-4 m/s^2.

Explanation:

The speed is constant and computing the speed from the distance and time for one full lap.

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Computing the v = 0.4 m / 100 s

v = 4 $\times$ 10^-3 m/s.

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= (4 $\times$ 10^-3)^2 / 0.037

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3 years ago

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3 years ago

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kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

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2 years ago

a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what

Andrews [41]

Answer:

v=9.6 km/s

Explanation:

Given that

The mass of the car = m

The mass of the truck = 4 m

The velocity of the truck ,u= 12 km/s

The final velocity when they stick = v

If there is no any external force on the system then the total linear momentum of the system will be conserve.

Pi = Pf

m x 0 + 4 m x 12 = (m + 4 m) x v

0 + 48 m = 5 m v

5 v = 48

$v=\dfrac{48}{5}\ km/s$

v=9.6 km/s

Therefore the final velocity will be 9.6 km/s.

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3 years ago