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Ede4ka [16]
3 years ago
12

The height of a flagpole is 8.5 meters tall. If the length of the meter stick shadow is 1.5 meters long, what would be the lengt

h of the flagpole’s shadow?
Physics
1 answer:
marin [14]3 years ago
3 0
Well, you could easily sow that for every full meter of height of the object, the length of the corresponding shadow would be 50 centimeters longer. therefore, you can multiply 8.50 meters by 1.5 and you would get an answer of 12.75 meters
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Name the forces acting on a plastic bucket container water held above ground level in your hand. Discuss why the forces acting o
SashulF [63]

There are two forces at play:

  • The gravitational force acting downward due to the mass of the bucket and the water that it contains.
  • The upward force that your hand exerts on the bucket.

If the magnitude of the force your hand exerts on the bucket equals the magnitude of the gravitational force, the bucket is in static equilibrium. That means the bucket is not moving and the forces acting on it balance each other out, making the net force 0.

Having 0 net force means the bucket doesn't undergo any acceleration, or change in motion.

5 0
3 years ago
a layer of sandstone is in contact with a mass of granite. the sandstone contains small fragments of the granite. which rock is
lara31 [8.8K]
The granite would be older. As millions of years go by, rocks are affected by weathering and erosion. These processes break down rocks and scatter them. Rocks are broken down into sediments, which mix with other layers, which could have been the reason how the layer of sandstone contains the small fragments of granite.
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3 years ago
A power plant produces 1000 MW to supply a city 40 km away. Current flows from the power plant on a single wire of resistance 0.
nikitadnepr [17]

Answer:

Current = 8696 A

Fraction of power lost = \dfrac{80}{529} = 0.151

Explanation:

Electric power is given by

P=IV

where I is the current and V is the voltage.

I=\dfrac{P}{V}

Using values from the question,

I=\dfrac{1000\times10^6 \text{ W}}{115\times10^3\text{ V}} = 8696 \text{ A}

The power loss is given by

P_\text{loss} = I^2R

where R is the resistance of the wire. From the question, the wire has a resistance of 0.050\Omega per km. Since resistance is proportional to length, the resistance of the wire is

R = 0.050\times40 = 2\Omega

Hence,

P_\text{loss} = \left(\dfrac{200000}{23}\right)^2\times2

The fraction lost = \dfrac{P_\text{loss}}{P}=\left(\dfrac{200000}{23}\right)^2\times2\div (1000\times10^6)=\dfrac{80}{529}=0.151

3 0
3 years ago
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goblinko [34]
Your answer is B, gases
6 0
4 years ago
Goodmorning I can’t seem to remember this can someone help me
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Explanation:

3 cause the triangle method of addition are connected to tips of one vector

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