Answer:
The empirical formula of the compound is = 
The name of the compound is potassium bromate.
Explanation:
Mass of potassium = 4.628 g
Moles of potassium = 
Mass of bromine = 9.457 g
Moles of bromine = 
Mass of oxygen = 5.681 g
Moles of oxygen = 
For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:
Potassium :

Bromine;

Oxygen ;

The empirical formula of the compound is = 
The name of the compound is potassium bromate.
radio waves, micro waves, infrared waves, visible light rays, ultra-violet rays, x-rays, then finally, gamma rays. I hope this was helpful to you.
Answer:
which one?
Explanation:
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Answer:
382.5J
Explanation:
<em>Use the formula:</em>
E = mcΔθ or Q = mcΔT
m = 100g
c = 0.45 J/g°C
ΔT or Δθ = 110 - 25 = 85°
<em>Sub in the values:</em>
E = 100 × 0.45 × 85
= 382.5J
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