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3 years ago

HELP PLEASE!!!

Chemistry

1 answer:

hjlf3 years ago

4 0

Answer:

1. 22 moles of FeCr2O7

2. 53.95 moles of O2

3. 77.25 moles of O2

Explanation:

4 FeCr2O7+ 8 K2CO3 + 1 O2-----------> 2 Fe2O3+ 8 K2CrO4 + 8 CO2

1. How many moles of FeCr2O7 are required to produce 44 moles of CO2?

Equate the moles of the compounds in the question

4 moles of FeCr2O7 produces 8 moles of CO2

(44 *4 / 8) moles of FeCr2O7 will produce 44 moles of CO2

= 44 *4 / 8

= 22 moles

2. How many moles of 02 is required to produce 107.9 moles of Fe2O3?

1 mole of O2 = 2 moles of Fe2O3

(107.9 *1 / 2) moles of O2 will be required to produce 107.9 moles of Fe2O3

= 107.9 * 1 / 2

= 53.95 moles

3. The ratio of moles for FeCr2O7 to O2 in the reaction is

4 : 1

309 : x ; solve for x

x = 309 * 1 / 4

x =77.25 moles of O2

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Answer:

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2 years ago

Moles of cations are in 1.35 mol of K2SO4

KatRina [158]

1.35 mole of K₂SO₄ contain 2.7 moles of cation.

Cations are positive ions. They are the ions of metallic elements.

To obtain the answer to the question, we'll begin by calculating the number of mole of cations in 1 mole of K₂SO₄.

K₂SO₄ (aq) —> 2K⁺ (aq) + SO₄²¯ (aq)

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From the balanced equation above,

1 mole of K₂SO₄ contains 2 moles of K⁺ (i.e cation).

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1 mole of K₂SO₄ contains 2 moles of K⁺ (i.e cation).

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Learn more: brainly.com/question/24707125

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2 years ago

Why are most solid ionic compounds electrically nonconductive, whereas aqueous solutions of ionic compounds are good conductors

Allisa [31]

Answer:

there must be free-moving electrons in a compound to conduct electricity.

in solid ionic compounds, there are no free electrons so it can't conduct electricity.

But in aqueous form the forces of attraction are broken and the ions (cations and anions) are free to move. This means there are free electrons that allow the aqueous compound to conduct electricity.

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2 years ago

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/

lara31 [8.8K]

Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

2.67%

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

You are calculating weight /Volume not weight/weight % or percent by mass of the solute

Here the weight/weight % or percent by mass of the solute is asked : So first convert the VOLUME OF SOLUTION into MASS

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