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3 years ago

HELP PLEASE!!!

Chemistry

1 answer:

hjlf3 years ago

4 0

Answer:

1. 22 moles of FeCr2O7

2. 53.95 moles of O2

3. 77.25 moles of O2

Explanation:

4 FeCr2O7+ 8 K2CO3 + 1 O2-----------> 2 Fe2O3+ 8 K2CrO4 + 8 CO2

1. How many moles of FeCr2O7 are required to produce 44 moles of CO2?

Equate the moles of the compounds in the question

4 moles of FeCr2O7 produces 8 moles of CO2

(44 *4 / 8) moles of FeCr2O7 will produce 44 moles of CO2

= 44 *4 / 8

= 22 moles

2. How many moles of 02 is required to produce 107.9 moles of Fe2O3?

1 mole of O2 = 2 moles of Fe2O3

(107.9 *1 / 2) moles of O2 will be required to produce 107.9 moles of Fe2O3

= 107.9 * 1 / 2

= 53.95 moles

3. The ratio of moles for FeCr2O7 to O2 in the reaction is

4 : 1

309 : x ; solve for x

x = 309 * 1 / 4

x =77.25 moles of O2

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This is an incomplete question, here is a complete question.

Determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices.

(a) $1s^22s^22p^63s^23p^5$

(b) $1s^22s^22p^63s^23p^63d^74s^2$

(d) $1s^22s^22p^63s^23p^63d^4s^1$

Answer :

(a) $1s^22s^22p^63s^23p^5$ → Halogen

(b) $1s^22s^22p^63s^23p^63d^74s^2$ → Transition metal

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$ → Transition metal

(d) $1s^22s^22p^63s^23p^63d^4s^1$ → Transition metal

Explanation :

Inert gas : These are the gases which lie in group 18.

Their general electronic configuration is: $ns^2np^6$ where n is the outermost shell.

Halogen : These are the elements which lie in group 17.

Their general electronic configuration is: $ns^2np^5$ where n is the outermost shell.

An alkali metal : These are the elements which lie in group 1.

Their general electronic configuration is: $ns^1$ where n is the outermost shell.

An alkaline earth metal : These are the elements which lie in group 2.

Their general electronic configuration is: $ns^2$ where n is the outermost shell.

Transition elements : They are the elements which lie between 's' and 'p' block elements. These are the elements which lie in group 3 to 12. The valence electrons of these elements enter d-orbital.

Their general electronic configuration is: $(n-1)d^{1-10}ns^{0-2}$ where n is the outermost shell.

(a) $1s^22s^22p^63s^23p^5$

The element having this electronic configuration belongs to the halogen family.

(b) $1s^22s^22p^63s^23p^63d^74s^2$

The element having this electronic configuration belongs to the transition family.

(c) $1s^22s^22p^63s^23p^63d^{10}4s^24p^6$

The element having this electronic configuration belongs to the transition family.

(d) $1s^22s^22p^63s^23p^63d^4s^1$

The element having this electronic configuration belongs to the transition family.

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