When [HClO]= 0.01 M & [ClO]^- = 0.03M & NaOH = 0.003 mol and
Ka = 3.5 x 10^-8
and the equation is:
HClO + NaOH → Na^+ + ClO^-
initial 0.01 0.003 0.03 0.03
-0.003 - 0.003 +0.003 + 0.003
Final 0.007 0 0.033 0.033
We can get the PH from this formula:
PH = Pka + ㏒[conjugent base/weak acid]
PH = -㏒Ka + ㏒[Na]/[HClO]
= - ㏒ 3.5x10^-8 + ㏒(0.033/0.007)
= 8.13
<span>No, I believe this is not an example of a chemical reaction.
What we actually see here is a physical change of the solution. Since we are adding
more water to an aqueous solution which is also made up mostly of water, what
we are simply basically doing is dilution. Since the solution is being diluted,
so definitely the color turned lighter.</span>
HI
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