The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻ → I₂ + 2e- and 2H₂O → O₂ + 4H⁺ + 4e⁻
<h3>What is Balanced Chemical Equation ?</h3>
The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.
Now write the equation for FeI₂
At cathode:
Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V
2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V
It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.
At anode:
2I⁻ → I₂ + 2e- Eo = - 0.54 V
2H₂O → O₂ + 4H⁺ + 4e⁻ Eo = -1.23 V
O₂ gas formed at anode.
Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻ → I₂ + 2e- and 2H₂O → O₂ + 4H⁺ + 4e⁻.
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Given is the specific heat of water equal to 4.18 Joule per gram per *C.
This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.
Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.
To do so we have formula
Q = m C (temperature difference)
Have a look at pic for answer
If your client receives a letter from SilverScript requesting proof of Creditable Coverage, they can ignore the letter is a false statement
<h3>What is Creditable coverage?</h3>
Creditable coverage is known to be a form of an health insurance, that consist of prescription drug and also other kinds of health benefit plan that is known to meets the minimum amount of qualifications.
Note that the types of creditable coverage plans are group and individual health plans, student health plans, and others.
It is not right to ignore any letter sent to you concerning the case above as it may be vital and as such, the statement of If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted proof of creditable coverage with the enrollment application, they can ignore the letter is a wrong/false statement.
Learn more about Creditable Coverage from
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H3PO4 + H2O <--> H3O+ + H2PO4- Ka1= ([H3O+][H2PO4-])/[H3PO4])
H2PO4- + H2O <--> H3O+ + HPO4^2- Ka2= ([H3O+][HPO4^2-])/[H2PO4-])
HPO4^2- + H2O <--> H3O+ PO4^3- Ka3= ([H3O+][PO4^3-])/[HPO4^2-])
Ka1 >> Ka2 = almost all the H3O+ is formed in the first step.
Ka3 will only happen under very basic conditions.
