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navik [9.2K]
3 years ago
13

Aerosol cans contain a written warning not to subject the can to high temperatures or incinerate. Suppose an aerosol can is heat

ed from 22°C to 110°C. What would you expect to happen? A) The contents of the aerosol can to vaporize. B) No change in volume or pressure; only an increase in temperature. C) The volume of the gas to decreases proportionately to the increase in temperature. D) The pressure in the can to increase proportionately to the increase in temperature.
Chemistry
2 answers:
Zanzabum3 years ago
8 0
D. there would be a proportional increase in pressure to temperature
oksian1 [2.3K]3 years ago
3 0

D, would be your final answer! :)

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Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I
vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- +  HS^- ⇄S^- + H3PO3.

<h3>What is an acid?</h3>

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- +  HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0
2 years ago
Select the true statements regarding these resonance structures of formate.? Each carbon-oyxgen bond is somewhere between a sing
son4ous [18]

Answer : Option 1) The true statement is each carbon-oxygen bond is somewhere between a single and double bond and the actual structure of format is an average of the two resonance forms.

Explanation : The actual structure of formate is found to be a resonance hybrid of the two resonating forms. The actual structure for formate do not switches back and forth between two resonance forms.

The O atom in the formate molecule with one bond and three lone pairs, in the resonance form left with reference to the attached image, gets changed into O atom with two bonds and two lone pairs.

Again, the O atom with two bonds and two lone pairs on the resonance form left, changed into O atom with one bond and three lone pairs. It concludes that each carbon-oxygen bond is neither a single bond nor a double bond; each carbon-oxygen bond is somewhere between a single and double bond.

Also, it is seen that each oxygen atom does not have neither a double bond nor a single bond 50% of the time.

7 0
3 years ago
Read 2 more answers
An aqueous solution contains 32.7% KCl (wt/wt%). what is the mole fraction of KCl in the solution
inna [77]

The mole fraction of KCl in the solution is 0.1051

calculation

mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)

moles=mass/molar mass

mass of KCl=32.7g

molar mass of KCl= 39 +35.5

moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles

find the moles of H2O= mass of H2O/molar mass

mass of H2O=100-32.7=67.3g

molar mass of H2O=( 1 x2) +16=18 g/mol

moles = 67.3/18 =3.739 moles

total moles=3.739+0.439=4.178 moles

mole fraction is therefore=0.439/4.178=0.1051

5 0
3 years ago
The transfer of energy changes the what of water
pentagon [3]
The water cycle ...........
7 0
3 years ago
Which of the following would increase the amount to dissolve a solid solute?
AVprozaik [17]

By stirring and increasing temperature, there is an increase in dissolving capacity of the solid solute.

<u>Explanation:</u>

If a solute is added to the solution, it doesn't get dissolve easily then we have to increase the temperature, which in turn increases the movement of the solvent (may be water) and the solute particles, thus increases the dissolving power of the solid solute. One more way is by constant stirring, that is by making more contact among the solvent as well as the solute particles there by increasing the solubility of solid solute.

5 0
3 years ago
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