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Temka [501]
3 years ago
9

What was your hypothesis? According to your data, do you think your hypothesis was correct? What is latent heat? How does it sho

w up on a phase diagram? When a substance is absorbing latent heat, what is happening to it? According to your data, what are the melting and boiling points of water? How can you tell? What practical applications are there for this procedure?
Physics
2 answers:
Elanso [62]3 years ago
6 0

Answer:  My hypothesis is that the water was going to melt at 25-degrees Celsius and boil at 100-degrees Celsius. It turns out that my hypothesis was almost correct, the ice actually melted a little sooner. It melted at 20-degrees Celsius. So my hypothesis was incorrect.

Explanation:

Iteru [2.4K]3 years ago
3 0

This is the answer i got.


  My hypothesis is that the water was going to melt at 25-degrees Celsius and boil at 100-degrees Celsius. It turns out that my hypothesis was almost correct, the ice actually melted a little sooner. It melted at 20-degrees Celsius. So my hypothesis was incorrect.

Latent heat is changing phase, and when a change in phase is accomplished at constant pressure temperature is constant. On the phase diagram, latent heat shows up as a "thermal plateau" where the graph is a flat line for a brief portion. The melting point of the ice was about 20-25 degrees celsius when it started turning into water, and at 100 degrees celsius when it started boiling. I could tell because the ice turned into water and the water got very hot.

The practical applications for this procedure were, ice,a pot,and a stove.

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lesya692 [45]

Answer:

Explanation:

Velocity of plane relative to ground V_pg = ?

Given the velocity in vector form ,

velocity of plane relative to air V_pw = 120 cos30 i + 120sin30j

V_wg = 60 i

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magnitude

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8 0
3 years ago
Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
zvonat [6]

Answer:

0.293I_0

Explanation:

When the unpolarized light passes through the first polarizer, only the component of the light parallel to the axis of the polarizer passes through.

Therefore, after the first polarizer, the intensity of light passing through it is halved, so the intensity after the first polarizer is:

I_1=\frac{I_0}{2}

Then, the light passes through the second polarizer. In this case, the intensity of the light passing through the 2nd polarizer is given by Malus' law:

I_2=I_1 cos^2 \theta

where

\theta is the angle between the axes of the two polarizer

Here we have

\theta=40^{\circ}

So the intensity after the 2nd polarizer is

I_2=I_1 (cos 40^{\circ})^2=0.587I_1

And substituting the expression for I1, we find:

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5 0
3 years ago
A wave is traveling at 241 m/s. It has a wavelength of 30.0 m. What is its frequency?
Feliz [49]

Answer:

A) 8.03Hz

Explanation:

f = V/λ

Where wavelength( λ )= 30m

Speed (V) =241m/S

f= 241/30=8.03Hz

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Waves: These are different because they aren't telling you or showing the entire spectrum just which they length that they are.

<em>It may confuse you but it makes sense to me (Sorry)</em>
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Hello,

It's D! hope I helped.
8 0
4 years ago
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