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Temka [501]
3 years ago
9

What was your hypothesis? According to your data, do you think your hypothesis was correct? What is latent heat? How does it sho

w up on a phase diagram? When a substance is absorbing latent heat, what is happening to it? According to your data, what are the melting and boiling points of water? How can you tell? What practical applications are there for this procedure?
Physics
2 answers:
Elanso [62]3 years ago
6 0

Answer:  My hypothesis is that the water was going to melt at 25-degrees Celsius and boil at 100-degrees Celsius. It turns out that my hypothesis was almost correct, the ice actually melted a little sooner. It melted at 20-degrees Celsius. So my hypothesis was incorrect.

Explanation:

Iteru [2.4K]3 years ago
3 0

This is the answer i got.


  My hypothesis is that the water was going to melt at 25-degrees Celsius and boil at 100-degrees Celsius. It turns out that my hypothesis was almost correct, the ice actually melted a little sooner. It melted at 20-degrees Celsius. So my hypothesis was incorrect.

Latent heat is changing phase, and when a change in phase is accomplished at constant pressure temperature is constant. On the phase diagram, latent heat shows up as a "thermal plateau" where the graph is a flat line for a brief portion. The melting point of the ice was about 20-25 degrees celsius when it started turning into water, and at 100 degrees celsius when it started boiling. I could tell because the ice turned into water and the water got very hot.

The practical applications for this procedure were, ice,a pot,and a stove.

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A 1.5m wire carries a 7 A current when a potential difference of 87 V is applied. What is the resistance of the wire?
kramer

Answer:

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

I would appreciate it!

3 0
3 years ago
Read 2 more answers
A force of 600 N is acting on a motorcycle that has a mass of 240 kg. What is the acceleration of the motorcycle?
Verdich [7]

Answer:

2.5m/s2

Explanation:

The following were obtained from the question:

F = 600N

M = 240 kg

a =?

Recall: F = Ma

a = F/M

a = 600/240

a = 2.5m/s2

Therefore, the acceleration of the motorcycle is 2.5m/s2

7 0
3 years ago
Read 2 more answers
What is the downward pull on an object due to gravity?
Strike441 [17]

Answer:

force of gravity

Explanation:

The force of gravity is that which draws the bodies towards the surface of the Earth.

 The force of gravity brakes the objects that move up and accelerates those that move down. It causes a parabolic movement in what we throw upwards,

3 0
3 years ago
Read 2 more answers
A 18-g paper clip is attached to the rim of a phonograph record with a diameter of 48 cm, spinning at 3.2 rad/s. What is the mag
Artist 52 [7]

Answer:

Magnitude of its angular momentum = 0.0017 kgm²/s

Explanation:

Angular momentum, L = Iω

I is mass moment of inertia and ω is angular velocity.

Phonograph is in disc shape,

\texttt{I for disc =}\frac{MR^2}{2}

Radius = 0.5 x 48 = 24 cm = 0.24 m

Angular velocity, ω = 3.2 rad/s

Mass, M = 18 g = 0.018 kg

Substituting

     L=\frac{0.018\times 0.24^2}{2}\times 3.2 =0.0017kgm^2/s

Magnitude of its angular momentum = 0.0017 kgm²/s

5 0
3 years ago
Calculate the ratio of the drag force on a jet flying at 1190 km/h at an altitude of 7.5 km to the drag force on a prop-driven t
Bond [772]

Answer:

\frac{D_{jet}}{D_{prop}}=2.865

Explanation:

Given data

Speed of jet Vjet=1190 km/h

Speed of prop driven Vprop=595 km/h

Height of jet 7.5 km

Height of prop driven transport 3.8 km

Density of Air at height 10 km p7.8=0.53 kg/m³

Density of air at height 3.8 km p3.8=0.74 kg/m³

The drag force is given by:

D=\frac{1}{2}CpAv^2\\

The ratio between the drag force on the jet to the drag force  on prop-driven transport is then given by:

\frac{D_{jet}}{D_{prop}}=\frac{(1/2)Cp_{7.5}Av_{jet}^2}{1/2)Cp_{3.8}Av_{prop}^2} \\\frac{D_{jet}}{D_{prop}}=\frac{p_{7.5}v_{jet}^2}{p_{3.8}v_{prop}}\\\frac{D_{jet}}{D_{prop}}=\frac{(0.53)(1190)^2}{(0.74)(595)^2}\\   \frac{D_{jet}}{D_{prop}}=2.865

4 0
3 years ago
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