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3 years ago

11

Subtract (8x^9+6)-(-7x^9)

1 answer:

Rainbow [258]3 years ago

6 0

15x^9+6 is the answer

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What is X + 96 = 96 + X

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commutative property i believe

Step-by-step explanation:

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The rule (x, y) ⇒ (x-2, y+3) will translate the way you want.

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3 years ago

I really don’t understand this and just need an explanation of how to do it.

sertanlavr [38]

$\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}$

$\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}$

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3 years ago

The product of two consecutive odd integers is 72. Write a quadratic equation to find the integers,

zimovet [89]

<u>Answer:</u>

$x^2 + x - 72 = 0$

<u>Explanation:</u>

We are given product of two consecutive odd integers is equal to 72.

Let one integer be x , then since these are consecutive and odd so the other integer will be equal to x + 1.

Their product is equal to 72. So,

x * (x + 1) = 72

=> $x^2 + x = 72$

=> $x^2 + x - 72 = 0$ is the required quadratic equation.

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3 years ago

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Step-by-step explanation:

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