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Andru [333]
3 years ago
8

What does the speed of sound depend on?

Physics
2 answers:
mr Goodwill [35]3 years ago
6 0
I believe it's 'A'. Hopefully this helps!~ :)
cluponka [151]3 years ago
5 0
I believe your answer would be "b"
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E inside = KQr_{1} /R^{3}  

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E  \begin{bmatrix}Blank Equation\end{bmatrix} proportional to 1/R3  

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E becomes 1/8 of the initial electric field.

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1. For a reaction to occur, energy must be
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For a reaction to occur, energy must be absorbed to break chemical bonds

<u>Explanation:</u>

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3 years ago
Which was an idea use to distribute the theory of plate tectonics
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How high is an object lifted if the total work done on it is 125 J and the force required to lift the object is 25 N? Use the eq
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3 years ago
The objective lens of a microscope has a focal length of 5.5mm. Part A What eyepiece focal length will give the microscope an ov
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Complete Question

The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 mm .

What eyepiece focal length will give the microscope an overall angular magnification of 300?

Answer:

The  eyepiece focal length is  f_e  = 0.027 \ m

Explanation:

From the question we are told that

    The focal length is  f_o =  5.5 \ mm =  -0.0055 \ m

This negative sign shows the the microscope is diverging light

     The  angular magnification is m = 300

     The  distance between the objective and the eyepieces lenses is  Z =  19 \ cm  = 0.19 \ m

Generally the magnification is mathematically represented as

        m  =  [\frac{Z - f_e }{f_e}] [\frac{0.25}{f_0} ]

Where f_e is the eyepiece focal length of the microscope

  Now  making f_e the subject  of the formula

         f_e  = \frac{Z}{1 - [\frac{M  *  f_o }{0.25}] }

substituting values

        f_e  = \frac{ 0.19 }{1 - [\frac{300  *  -0.0055 }{0.25}] }

         f_e  = 0.027 \ m

     

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3 years ago
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