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Andru [333]
3 years ago
8

What does the speed of sound depend on?

Physics
2 answers:
mr Goodwill [35]3 years ago
6 0
I believe it's 'A'. Hopefully this helps!~ :)
cluponka [151]3 years ago
5 0
I believe your answer would be "b"
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D

Explanation:

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5. A 1.2 m guitar string is under a tension of 888 N. The waves produced on the string (when
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A small, closed chamber of gas is heated. When the gas in the chamber expands,it does 5 J of work on a piston. The gas has an in
Anestetic [448]

Given:

Work done, W = 5 J

Initial energy = 8J

Final energy = 30J

Let's determine if the work done have a positive or nrgative value.

Appy the equation for the first lae of thermodynamics:

\Delta U=Q-W

Where:

U is the change in internal energy

Q is the added heat

W is the work done

To find the work done here, we have:

Rewrite the formula for W

W=Q-\Delta U

Where:

ΔU = 30J - 8J = 22J

Q = 5J

Thus, we have:

\begin{gathered} W=5J-22J \\  \\ W=-17J \end{gathered}

Therefore, the work done here is -17J.

This means the work done in this scenario has a negative value.

ANSWER:

The work done in this scenario has a negative value

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1 year ago
You wad up a piece of paper and throw it into the wastebasket. How far will
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Answer:

Since the paper is wadded up tight, and if there's any

air resistance left we assume there isn't any, it might

just as well be a stone that's tossed.  This is just a

stripped down projectile situation.

You said "an angle of 36 degrees", but you didn't say relative

to what.  I'll assume that it's 36 degrees above horizontal, and

now I'll proceed to answer the question with the information that

I just gave myself.

-- The vertical component of the velocity is  1.4 sin(36)

                                                                        = 0.823 m/s up.

-- The projectile rises for (0.823/9.8) second, runs out of gas,

and then falls for another (0.823/9.8) second to its original height.

So it's in the air for

                                  2 (0.823/9.8) = 0.168 second

                                                            (not very long at all)

-- The horizontal component of the velocity is  1.4 cos(36)

                                                                           = 1.133 m/s  

                                                             and it doesn't change.

-- During the 0.168 second that it's in the air,

the wad travels horizontally

                                              (0.168 s) x (1.133 m/s)

                                          =            0.19 meter

                                              (19 cm, ~ 7.5 inches)

If you find my mistake on this one, please please tell me.  

As of now, it looks like with that velocity at that angle, your

paper wad only makes it 7.5 inches from your hand into the can.

Explanation:

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Answer:

Plasma membrane

Explanation:

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