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Verizon [17]
4 years ago
8

Which explains the information needed to calculate speed and velocity?

Physics
1 answer:
Anestetic [448]4 years ago
3 0

Both require time, but velocity requires displacement and speed requires distance.

Explanation:

Speed and velocity are two different quantities. In fact:

- Speed is a scalar quantity, which gives a measure of how fast an object is moving, regardless of its direction. Therefore, it only has a magnitude, which is given by the ratio between distance covered and time taken:

s=\frac{distance}{time}

Therefore, speed does not take into account the direction of motion.

- Velocity, on the other hand, is a vector quantity, so it has magnitude and a direction.

The magnitude of the velocity is given by

v=\frac{displacement}{time}

where displacement is a vector connecting the initial point with the final point of motion of an object.

The direction of the velocity corresponds to the direction of the displacement.

It must be noted also that in certain situations, the average velocity is zero, while the speed is not zero: for example, for an object completing a circle in a certain time interval, its speed is not zero, while its velocity is zero (because the object returns to the starting point, so the displacement is zero.

Therefore, the correct answer is

Both require time, but velocity requires displacement and speed requires distance.

Learn more about speed and velocity:

brainly.com/question/8893949

brainly.com/question/5063905

brainly.com/question/5248528

#LearnwithBrainly

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Two large metal plates of area 0.7 m2 face each other. They are 5.1 cm apart and have equal but opposite charges on their inner
german

Explanation:

The given data is as follows.

    Area (A) = 0.7 m^{2}.

  Electric field between the plates, (E) = 55 N/C

Since, electric field is related to surface charge density as follows.

          \sigma = \frac{Q}{A}

Also,    E = \frac{\sigma}{\epsilon_{o}}

or,        \sigma = \epsilon_{o} E

Therefore, charge will be calculated as follows.

          Q = \sigma \times A = \epsilon_{o} E \times A

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4 years ago
A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent
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Answer:

The position is  P  =  47.4 \ m relative to the base of the ocean

Explanation:

From the question we are told that

    The angle made by the incline with the horizontal is \theta =  24.0 ^o

    The constant acceleration is a =  3.82 \ m/s^2

    The distance covered is d =  60.0 \ m

    The height of the cliff is h  =  50 .0 \ m

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      v^2 = u^2 +  2ad

The initial velocity of the car is  u= 0

So

     v^2 =  2ad

substituting values

     v^2 = 2 *  3.82 * 60

    v =  21.4 \ m/s

The vertical component of this velocity is

    v_v  =  -v * sin(\theta )

substituting values

    v_v  = -21.4 * sin(24.0)

    v_v  = -8.7 \ m/s

The negative sign is because is moving in the negative direction of the y-axis

The horizontal  component of this velocity is

     v_h  =  v * cos (\theta)

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given that time cannot be negative

      t = 2.42 \ s

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substituting values

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