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3 years ago

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A pulley is able to lift a mass of 25 kg 0.30 m with an applied force of 50 N over a distance of 1.5 m. What is the ideal mechan

ical advantage of the pulley system?

1 answer:

spin [16.1K]3 years ago

7 0

The ideal mechanical advantage of the pulley system is 3

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Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the

Aleksandr-060686 [28]

Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

Explanation:

The new distance is

$\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}$

The force can be calculated by the formula

$F=k\frac{q1q2}{(r^{\prime})^2}$

Here, k is the constant whose value is

$k=9\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the force will be

$\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}$

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1 year ago

Why does the temperature decreases at higher altitudes

sergey [27]

temperature decreases at higher altitudes because as air rises the pressure decreases.

3 0

2 years ago

Which is an example of transfroming potential energy to kinetic

Rudik [331]

Answer:

A ball being dropped to the ground

6 0

3 years ago

Read 2 more answers

Use a common denominator to find-2/3 + -4/5

Juliette [100K]

Answer:

-22/15

Explanation:

the least common denominator is 15 so first you multiply -2/3 by 5 in both the numerator and denominator making it -10/15

Then you do the same to -4/5 except you multiply the numerator and denominator by 3 giving you -12/15

If you add -10/15+ -12/15 you get -22/15

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3 years ago

A very long straight wire has charge per unit length 1.56×10−10 C/m .

77julia77 [94]

Answer:

The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.

Explanation:

using Guass law,

(guessing that a cylinder of radius r and length L around wire such that wire is at centre )

E. A = qin / e0

E ( 2πr L ) = (1.56 x $10^{-10}$ x L) / (8.85 x $10^{-12}$ )

E = (1.56 x $10^{-10}$ ) / (2πr x 8.85 x $10^{-12}$ )

so 2.40 = (1.54 x $10^{-10}$ ) / (2πr x 8.85 x $10^{-12}$ )

2.40 (6.284r) = 0.174 x 10²

15.0816r = 17.4

r = 1.1537m

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2 years ago