Given:
The magnitude of each charge is q1 = q2 = 1 C
The distance between them is r = 1 m
To find the force when distance is doubled.
Explanation:
The new distance is

The force can be calculated by the formula

Here, k is the constant whose value is

On substituting the values, the force will be

temperature decreases at higher altitudes because as air rises the pressure decreases.
Answer:
A ball being dropped to the ground
Answer:
-22/15
Explanation:
the least common denominator is 15 so first you multiply -2/3 by 5 in both the numerator and denominator making it -10/15
Then you do the same to -4/5 except you multiply the numerator and denominator by 3 giving you -12/15
If you add -10/15+ -12/15 you get -22/15
Answer:
The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.
Explanation:
using Guass law,
(guessing that a cylinder of radius r and length L around wire such that wire is at centre )
E. A = qin / e0
E ( 2πr L ) = (1.56 x
x L) / (8.85 x
)
E = (1.56 x
) / (2πr x 8.85 x
)
so 2.40 = (1.54 x
) / (2πr x 8.85 x
)
2.40 (6.284r) = 0.174 x 10²
15.0816r = 17.4
r = 1.1537m