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Neko [114]
2 years ago
7

2. Xét một điểm nằm trên vành ngoài của lốp xe máy cách trục bánh xe môtô 25cm.

Physics
1 answer:
Rashid [163]2 years ago
6 0

Answer:

b. Cho biết tốc độ của xe là 4m/s. Hãy tính tốc độ góc của điểm trên vành ngoài bánh xe.

Explanation:

#CarryOnLearning

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A frame hanging on a wall is held by two cables. The tension in each cable is 30 N, and the cables make an angle of 45° with the
Dimas [21]

Answer: option D) 42.4 N

The weight of the frame is balanced by the vertical component of tension.

W = T sin θ + T sin θ = 2 T sin θ

The tension in each cable is T = 30 N

Angle made by the cables with the horizontal, θ = 45°

⇒ W = 2×30 N × sin 45° = 2 × 30 N × 0.707 = 42.4 N

Hence, the weight of the frame is 42.4 N. Correct option is D.


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3 years ago
What do you understand by family health?<br>​
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Answer:

Family health provides, besides the cure of disease, various activities and programs in prevention, rehabilitation, and health promotion for all members of families/households. pls mark me branilest

3 0
2 years ago
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Many galaxies appear to have supermassive black holes in their centers powering active galactic nuclei (also called AGN). The Sc
Lena [83]

Answer:i dont remember

Explanation: ?>>> confused

5 0
3 years ago
If a battery causes a wire to carry a current of 4 Amps how many coulombs of charge flow past any point in the wire in 3 seconds
BabaBlast [244]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

According to above question ~

  • Current (I) = 4 Amperes

  • Time (t) = 3 seconds

  • Charge (q) = ?

Let's find the charge (q) by using formula ~

  • I =  \dfrac{q}{t}

  • 4 =  \dfrac{q}{3}

  • q = 4 \times 3

  • q = 12 \:  \: coulombs

Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds

7 0
3 years ago
The membrane that surrounds a certain type of living cell has a surface area of 5.3 x 10-9 m2 and a thickness of 1.1 x 10-8 m. A
kotykmax [81]

Answer:

2.1\times 10^{-12} c

Explanation:

We are given that

Surface area of membrane=5.3\times 10^{-9} m^2

Thickness of membrane=1.1\times 10^{-8} m

Assume that membrane behave like a parallel plate capacitor.

Dielectric constant=5.9

Potential difference between surfaces=85.9 mV

We have to find the charge resides on the outer surface of membrane.

Capacitance between parallel plate capacitor is given by

C=\frac{k\epsilon_0 A}{d}

Substitute the values then we get

Capacitance between parallel plate capacitor=\frac{5.9\times 8.85\times 10^{-12}\times 5.3\times 10^{-9}}{1.1\times 10^{-8}}

C=0.25\times 10^{-12}F

V=85.9 mV=85.9\times 10^{-3}

Q=CV

Q=0.25\times 10^{-12}\times 85.9\times 10^{3}=2.1\times 10^{-12} c

Hence, the charge resides on the outer surface=2.1\times 10^{-12} c

5 0
3 years ago
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