The momentum p of a moving particle is the product between its mass, m, and tis velocity, v:

In our problem, we know

and

, and using the relationship mentioned above, we can find the mass m of the particle:
In that case, their momentum must be equal.
So, m1v1 = m2v2
20 * 20 = 40 * v2
v2 = 400 / 40
v2 = 10
In short, Your Answer would be: 10 m/s
Hope this helps!
Answer:
Explanation:
Rx = -28.2 units
Ry = 19.6 units
magnitude of R = √ [( - 28.2 )² + ( 19.6 ) ]
= √ ( 795.24 + 384.16 )
= 34.34 units
If θ be the angle measured counterclockwise from the +x-direction
Tanθ = 19.6 / - 28.2 = -0.695
θ = 180 - 34.8
= 145.2° .
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Answer: T= 715 N
Explanation:
The only external force (neglecting gravity) acting on the swinging mass, is the centripetal force, which. in this case, is represented by the tension in the string, so we can say:
T = mv² / r
At the moment that the mass be released, it wil continue moving in a straight line at the same tangential speed that it had just an instant before, which is the same speed included in the centripetal force expression.
So the kinetic energy will be the following:
K = 1/2 m v² = 15. 0 J
Solving for v², and replacing in the expression for T:
T = 1.9 Kg (3.97)² m²/s² / 0.042 m = 715 N