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RSB [31]
2 years ago
13

A moving fan continues to move for a while even after switched off, why? ​

Physics
2 answers:
babymother [125]2 years ago
7 0

Answer:

A fan has a property to follow it's circular motion even when the power supply is cut. A moving fan continues to move for a while even after switched off.

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

dem82 [27]2 years ago
4 0

Answer:

due to the inertia of motion, the fan continues to move for some time even after switching it off.

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A portable music player, operating with four 1.5 V cells connected in series, provides a resistance of 15 000 Ω. What amount of
nata0808 [166]

Answer:

Explanation:

Given that,

A portable music player is operating with 4 cell batteries connected in series, and each cell has a P.D of 1.5V.

Then,

Total potential difference is

P.D_total = V1 + V2 + V3 + V4

P.D_total = 1.5 + 1.5 + 1.5 + 1.4

P.D_total = 6V.

The music player provides a resistance of 15,000Ω

R = 15,000Ω

We want to find the current (I) flowing through the music player?

Using ohms law

V = IR

Where

V is the potential difference

I is the current

R is the resistance

Therefore,

I = V/R

I = 6 / 15,000

I = 4 × 10^-4 A

I = 0.4 × 10^-3 A

I = 0.4 mA.

So, 0.4mA is passing through the music player

7 0
3 years ago
It is night. Someone who is 4 feet tall is walking away from a street light at a rate of 8 feet per second. The street light is
KiRa [710]

Answer: 4 ft/s

Explanation:

Given

height of man=4 ft

speed of person v=8 ft/s

height if street light=12 ft

Let x be the distance between person and street light and y be the length of his shadow

From diagram

as the two triangle ADE and ABC are similar therefore we can say that

\frac{4}{12}=\frac{y}{x+y}

\frac{1}{3}=\frac{y}{x+y}

x+y=3y

x=2y

differentiate above Equation w.r.t time we get

\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} y}{\mathrm{d} t}

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{8}{2}=4 ft/s

6 0
2 years ago
How much gravitational force do two lead balls with a mass of 8 kilograms, the centers of mass of which are 17 cm apart, affect
Arisa [49]

Answer:

1.48×10⁻⁷ Newtons

Explanation:

From the question,

According to newton's law of universal gravitation.

F = Gmm'/r²........................ Equation 1

F = gravitational force, G = gravitational constant, m = mass of the first ball, m' = mass of the second ball, r = distance between the balls.

Given: m = m' = 8 kg, r = 17 cm = 0.17 m,

Constant : G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

F =  (6.67×10⁻¹¹×8×8)/(0.17²)

F = 1.48×10⁻⁷ N

7 0
3 years ago
What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE ar
Papessa [141]

Answer:

9.78 m/s²

Explanation:

To solve this, we use the gravitational formula

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

M = mass of the planet

r = radius of the planet

From the question, we got that the mass of the planet is

M = 9ME, where ME = 5.95*10^24

M = 9 * 5.95*10^24

M = 5.355*10^25 kg

Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6

R = 3 * 6.37*10^6

R = 1.911*10^7 m

On applying the values of both R and M to the equation, we get

g = GM/r²

g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²

g = 3.57*10^15/3.65*10^14

g = 9.78 m/s²

Therefore, the acceleration due to gravity on the planet is 9.78 m/s²

Please vote brainliest if it helped you <3

5 0
3 years ago
Particles that attract each other are
photoshop1234 [79]
B. I belive :)
Hopes this helps
3 0
2 years ago
Read 2 more answers
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