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3 years ago

[11]. Of these four liquids, which is the most viscous?

1 answer:

6 0

The most viscous among the choices is D. Honey at room temperature.

Viscosities of liquids typically vary with temperature. The higher the temperature, the lower the viscosity. Among the choices, only motor oil and honey appear to be the most viscous. The clue that helps determined the answer are the words "hot" and "room temperature". Hot motor oil is less viscous, while honey at room temperature is more viscous. Even comparing their viscosities at room temperature, honey already has a higher viscosity than motor oil.

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Which two changes in state are most represented in water cycle

Nadya [2.5K]

Answer: Evaporation and condensation are the two changes in state which are most represented in water cycle.

Explanation:

A process of circulation of water by passing through different states between the atmosphere, oceans and land is known as water cycle.

In water cycle, the most represented changes in state are evaporation and condensation. As during evaporation, the water present in the oceans, rivers, wells or on the land evaporates because of the heat from the sun as a result the liquid state is changing into gas.

Whereas, during condensation gas or water vapours changes into liquid. For example, when water condenses in the atmosphere it results in the formation of clouds.

Thus, it can be concluded that evaporation and condensation are the two changes in state which are most represented in water cycle.

3 0

3 years ago

How many diatomic molecules are there? List all of them

wariber [46]

Answer: Br2 I2 N2 Cl2 H2 O2 F2 (7 elements)

Explanation:

How to remeber this: Hal-NOH or BrINCIHOF

halogens Nitrogen, Oxygen, and Hydrogen.

7 0

3 years ago

Give the structure of the product obtained when cyclopropene loses a proton. Will the product be aromatic or not?

astra-53 [7]

Answer:

not aromatic

Explanation:

Cyclopropene -

as the compound is is made to lose a proton , and gains a negative charge on its ring ,

Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,

According to Huckel 's rule ,

The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,

And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.

Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .

Therefore , the compound becomes not aromatic or anti - aromatic .

3 0

3 years ago

Lithium has two stable isotopes with masses of 6.01512 amu and 7.01600 amu. The average molar mass of Li is 6.941 amu. What is t

Dvinal [7]

Answer : The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'

For Li isotope-1 :

Mass of Li isotope-1 = 6.01512 amu

Fractional abundance of Li isotope-1 = x

For Li isotope-2 :

Mass of Li isotope-2 = 7.01600 amu

Fractional abundance of Li isotope-2 = 100-x

Average atomic mass of Li = 6.941 amu

Putting values in equation 1, we get:

$6.941=[(6.01512\times x)+(7.01600\times (100-x))]$

By solving the term 'x', we get:

$x=694.048$

Percent abundance of Li isotope-1 = $\frac{694.048}{100}=6.94\%$

Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %

6 0

3 years ago

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/

lara31 [8.8K]

Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

2.67%

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

You are calculating weight /Volume not weight/weight % or percent by mass of the solute

Here the weight/weight % or percent by mass of the solute is asked : So first convert the VOLUME OF SOLUTION into MASS

Density of potassium nitrate in water KNO3 = 2.11 g/mL

$density=\frac{mass}{volume}$