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Ne4ueva [31]
3 years ago
8

Choose the glycolytic enzymes that require ATP

Chemistry
1 answer:
grigory [225]3 years ago
6 0

Answer:

Explanation:

Glycolytic pathway is a multi-enzyme pathway (involving ten reactions) showing the breakdown of glucose to form pyruvate.

The pathway is divided into two phases; energy requiring and energy yielding phase. In the energy requiring phase, ATP is used and converted to ADP while in the energy yielding ATP is produced from ADP.

The question asks about the energy requiring phase and the enzymes involved, which are

c. Hexokinase catalyzes the conversion of glucose to glucose-6-phosphate. Here, one phosphate group from ATP is attached to glucose to form glucose-6-phosphate and ADP is released in the process

d. Phosphofructokinase catalyzes the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate.

Here, one phosphate group from ATP is attached to frutose-6-phosphate to form fructose-1,6-bisphosphate and ADP is released in the process.

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calculate the quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis
abruzzese [7]

The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.

Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.

Calculation :-

using the titration equation,

M₁V₁ = M₂V₂

substituting values

V₁ = M₂ V₂/M₁

  = 0.2 × 10 ml /0.01

= 2/0.01 ml

= 200 ml.

A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.

Learn more about solvolysis here:-brainly.com/question/29555642

#SPJ4

<u />

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.

5 0
1 year ago
9. What type of bond is pictured in the image below?
mestny [16]

Answer:

metallic bond

because this diagram is electron gas theory which shows metallic bond

8 0
3 years ago
What is the percent error for the experiment if the actual density is
OLga [1]

Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual density = 2.49g/mL

error = 2.49 - 1.47 = 1.02

We have

p(\%) =  \frac{1.02}{2.49}  \times 100 \\ = 40.96385542...

We have the final answer as

<h3>40.96 %</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
What compound is formed when 2,2-dimethyloxirane (2-methyl-1,2-epoxypropane) is treated with ethanol containing sulfuric acid
vladimir1956 [14]

Answer:

2-ethoxy-2-methylpropan-1-ol

Explanation:

On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid H_2SO_4). The acid medium will produce the <u>hydronium ion</u> (H^+). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.

See figure 1

I hope it helps!

3 0
3 years ago
A sample of metal has a mass of 16.5916.59 g, and a volume of 5.815.81 mL. What is the density of this metal
Oxana [17]

Answer:

=> 2.8554 g/mL

Explanation:

To determine the formula to use in solving such a problem, you have to consider what you have been given.

We have;

mass (m)     = 16.59 g

Volume (v) =  5.81 mL

From our question, we are to determine the density (rho) of the rock.

The formula:

p = \frac{m}{v}

Substitute the values into the formula:

​p = \frac{16.59 g}{5.81 mL} \\   = 2.8554 g/mL

= 2.8554 g/mL

Therefore, the density (rho) of the rock is 2.8554 g/mL.

5 0
2 years ago
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