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2 years ago

Choose the glycolytic enzymes that require ATP

Chemistry

1 answer:

grigory [225]2 years ago

6 0

Answer:

Explanation:

Glycolytic pathway is a multi-enzyme pathway (involving ten reactions) showing the breakdown of glucose to form pyruvate.

The pathway is divided into two phases; energy requiring and energy yielding phase. In the energy requiring phase, ATP is used and converted to ADP while in the energy yielding ATP is produced from ADP.

The question asks about the energy requiring phase and the enzymes involved, which are

c. Hexokinase catalyzes the conversion of glucose to glucose-6-phosphate. Here, one phosphate group from ATP is attached to glucose to form glucose-6-phosphate and ADP is released in the process

d. Phosphofructokinase catalyzes the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate.

Here, one phosphate group from ATP is attached to frutose-6-phosphate to form fructose-1,6-bisphosphate and ADP is released in the process.

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The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:

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Answer:

Enthalpy change for the reaction is -67716 J/mol.

Explanation:

Number of moles of $AgNO_{3}$ in 50.0 mL of 0.100 M of $AgNO_{3}$

= Number of moles of HCl in 50.0 mL of 0.100 M of HCl

= $\frac{0.100}{1000}\times 50.0$ moles

= 0.00500 moles

According to balanced equation, 1 mol of $AgNO_{3}$ reacts with 1 mol of HCl to form 1 mol of AgCl.

So, 0.00500 moles of $AgNO_{3}$ react with 0.00500 moles of HCl to form 0.00500 moles of AgCl

Total volume of solution = (50.0+50.0) mL = 100.0 mL

So, mass of solution = ( $100.0\times 1.00$ ) g = 100 g

Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)

= $\frac{-m_{solution}\times C_{solution}\times \Delta T_{solution}}{0.00500mol}$

= $\frac{-100g\times 4.18\frac{J}{g.^{0}\textrm{C}}\times [24.21-23.40]^{0}\textrm{C}}{0.00500mol}$

= -67716 J/mol

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2 years ago

Which would exert more pressure on the floor, a 100kg man wearing snow shoes or a 60kg woman wearing high heels? PLEASE EXPLAIN

iris [78.8K]

Pressure can be defined as the force acting on a perpendicular surface per unit area.

Force exerted by a man of mass 100 kg wearing snow shoes = m.a

Where m = mass of the man = 100 kg

a = acceleration due to gravity= 9.8 $m/s^{2}$

Force exerted by the man of mass 100 kg = $100 kg(9.8 m/s^{2}) = 980 N$

Force exerted by woman of mass 60 kg = $60 kg(9.8 m/s^{2}) = 588 N$

Force exerted by 100 kg man is greater than that exerted as 60 kg woman. The area on which this force is acting determines the pressure. Pressure is inversely proportional to the area on which the force acts. Therefore, the pressure exerted by 100 kg man wearing snow shoes is less than the pressure exerted by a 60 kg woman woman wearing high heels as the force acts over a larger area when the man wears snow shoes when compared to the force exerted over a smaller area in case of the woman wearing high heels.

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