The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.
Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.
Calculation :-
using the titration equation,
M₁V₁ = M₂V₂
substituting values 
V₁ = M₂ V₂/M₁
   = 0.2 × 10 ml /0.01
 = 2/0.01 ml
 = 200 ml.
A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.
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<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>
Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.
 
        
             
        
        
        
Answer:
metallic bond 
because this diagram is electron gas theory which shows metallic bond
 
        
             
        
        
        
Answer:
<h3>The answer is 40.96%</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula

From the question
actual density = 2.49g/mL
error = 2.49 - 1.47 = 1.02
We have

We have the final answer as
<h3>40.96 %</h3>
Hope this helps you
 
        
                    
             
        
        
        
Answer:
2-ethoxy-2-methylpropan-1-ol
Explanation:
On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid 
). The acid medium will produce the <u>hydronium ion</u> (
). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.
See figure 1
I hope it helps!
 
        
             
        
        
        
Answer:
=> 2.8554 g/mL
Explanation:
To determine the formula to use in solving such a problem, you have to consider what you have been given.
We have;
mass (m)     = 16.59 g
Volume (v) =  5.81 mL
From our question, we are to determine the density (rho) of the rock.
The formula:

Substitute the values into the formula:

= 2.8554 g/mL
Therefore, the density (rho) of the rock is 2.8554 g/mL.