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Ne4ueva [31]
4 years ago
8

Choose the glycolytic enzymes that require ATP

Chemistry
1 answer:
grigory [225]4 years ago
6 0

Answer:

Explanation:

Glycolytic pathway is a multi-enzyme pathway (involving ten reactions) showing the breakdown of glucose to form pyruvate.

The pathway is divided into two phases; energy requiring and energy yielding phase. In the energy requiring phase, ATP is used and converted to ADP while in the energy yielding ATP is produced from ADP.

The question asks about the energy requiring phase and the enzymes involved, which are

c. Hexokinase catalyzes the conversion of glucose to glucose-6-phosphate. Here, one phosphate group from ATP is attached to glucose to form glucose-6-phosphate and ADP is released in the process

d. Phosphofructokinase catalyzes the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate.

Here, one phosphate group from ATP is attached to frutose-6-phosphate to form fructose-1,6-bisphosphate and ADP is released in the process.

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How did the elements begin to stratify?
Bogdan [553]

Answer:

The process of elemental stratification relies on the diffusion velocity, which causes the migration of the different chemical elements within stars.

Explanation:

8 0
3 years ago
Calcium cyclamate, Ca(C₆H₁₁NHSO₃)₂, is an artificial sweetener used in many countries around the world but is banned in the Unit
xeze [42]

Answer:

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃;

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃;

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

Explanation:

First, let's see the reactants for the first reaction and how they dissociate:

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

BaCO₃ → Ba²⁺ + CO₃²⁻ (Barium is from group 2, so its cation has charge +2)

So, to form the products, the cation of one will join the anion of others. The amount of the cation will be the charge of the anion, and the amount of the anion will be the charge of the cation:

H⁺ + CO₃²⁻ → H₂CO₃

Ba²⁺ + C₆H₁₁NHSO₃⁻ → Ba(C₆H₁₁NHSO₃)₂

The reaction then is:

HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The number of elements must be the same on both sides, so the balanced equation is

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The treatment with H₂SO₄ will produce:

H₂SO₄ → 2H⁺ + SO₄⁻²

Ba(C₆H₁₁NHSO₃)₂ → Ba²⁺ + C₆H₁₁NHSO₃⁻

The balanced reaction will be then:

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃

In the last step, HC₆H₁₁NHSO₃ will react with Ca(OH)₂

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

Ca(OH)₂ → Ca²⁺ + 2OH⁻

The balance reaction will be:

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

3 0
3 years ago
Which electromagnetic wave does the student replace the question mark with in the table?
marysya [2.9K]

Answer:

B) Gamma

Explanation:

Gamma is by far the most powerful, and only one that can produce this much energy

4 0
2 years ago
Read 2 more answers
16.H2O (water) and NaCl (salt) are _________ that are in salt water, which is a(n) __________. Water and salt contain the ______
trapecia [35]
#1...<span>Mixture; compounds; elements
#2...Protons 

</span>
4 0
3 years ago
Please help me on Q2 <br> I’ll be so incredibly grateful!!
eimsori [14]

Answer:

No. of neutrons = 27 - 13 = 14

No. of protons = No. of electrons = 13

Hope it helps you

4 0
3 years ago
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