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Varvara68 [4.7K]
3 years ago
14

Jill pulls on a rope to lift a 12 kg pail out of a well, while the clumsy Jack watches. For a 10.0 meter segment of the lift, sh

e lifts the bucket straight up at constant speed. How much power is required to complete this task in 5.0 seconds?
Physics
1 answer:
kvv77 [185]3 years ago
7 0
Definition of power is the amount of work done per unit of time:
P=\frac{W}{t}
We need to calculate the work done by Jill. 
Work is defined as the force acting along the path: 
W=F\cdot h
In this case, Jill is working against the force of gravity along the path of 10 meters:
W=mgh=12\cdot9.81\cdot 10=1177.2 J
Now we can calculate the power:
P=\frac{1177.2}{5}= 235.44 W
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Answer:

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The given function represents the position of a particle traveling along a horizontal line. s(t) = 2t3 − 3t2 − 12t + 6 for t ≥ 0
avanturin [10]

Answer:

(a) v(t) = 6t^2 - 6t - 12, a(t) = 12t - 6

(b) When 0 \leq t < 0.5, object is slowing down, when t > 0.5 object is speeding up.

Explanation:

(a) To get the velocity function, we need to take the derivative of the position function.

v(t) = \frac{ds(t)}{dt}  = (2t^{3})^{'} - (3t^{2})^{'} - (12t)^{'} + 6^{'} = 6t^{2} - 6t - 12

To get the acceleration function, we need to take the derivative of the velocity function.

a(t) = \frac{dv(t)}{dt} = (6t^{2})^{'} - (6t)^{'} - (12)^{'} = 12t - 6

(b) The object is slowing down when velocity is decreasing by time (decelerating) hence a < 0

12t - 6 < 0 \\12t < 6 \\t < 0.5

On the other hand, object is speeding up when a > 0

12t - 6 > 0 \\12t > 6 \\t > 0.5

Therefore, when 0 \leq t < 0.5, object is slowing down, when t > 0.5 object is speeding up.

6 0
3 years ago
Salt is dissolved in a flask of tap water. Distilling the mixture causes the salt to separate from the water. Which type of ener
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djyliett [7]

<u>Answer</u>

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<u>Explanation</u>

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V₂ = 10 × 310

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