To solve this problem we will apply the concepts related to the conservation of kinetic energy and elastic potential energy. Thus we will have that the kinetic energy is

And the potential energy is

Here,
m = mass
v = Velocity
x = Displacement
k = Spring constant
There is equilibrium, then,
KE = PE

Our values are given as,

Replacing we have that


Therefore the speed of the cart is 2.19m/s
Answer:
Rain came along with lower temps
Explanation:
There was no rain on the warmer days
There were more clouds as the week went on
and the temp decreased during the week so rain came with lower temps is the only one that can be correct
Answer:
Ok so there are many ways to go at this.
you can get a zip lock bag and put a bunch of plastic around the egg inside the bag. (image down below)
Just anything to slow down the descent speed.
Cushion the egg so that something other than the egg itself absorbs the impact of landing.
Explanation:
Explanation:
A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision. An inelastic collision is one in which part of the kinetic energy is changed to some other form of energy in the collision.
W=fd
W= (125N) (3.5m)
W= 437.5 J