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goldfiish [28.3K]
3 years ago
14

Draw the products for the proton transfer reaction between sodium hydride and ethanol

Chemistry
1 answer:
Eduardwww [97]3 years ago
5 0
Sodium hydride has the formula NaH where we have a sodium ion, Na⁺ and a hydride ion, H⁻. Hydride is an incredibly powerful base. While it is capable of acting as a nucleophile, if there is an acidic proton in a molecule, the hydride will deprotonate the molecule and grab the most acidic proton.

The pka of H⁻ is 35. The pka of ethanol is 16. The species with the larger pka is the better base and is capable of deprotonating the species with the smaller pka. Therefore, the hydride will deprotonate the acidic -OH proton of the alcohol in the following reaction:

CH₃CH₂OH + NaH → CH₃CH₂O⁻Na⁺ + H₂

The result of the reaction is the hydride deprotonates the proton of the alcohol and forms the alkoxide, which is a sodium salt. This reaction also leads to the formation of H₂ gas which ensures that this reaction is not reversible as the H₂ leaves the reaction mixture upon formation.
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When Earth receives energy from the Sun, ____. a. some energy is reflected back into space b. some is absorbed by the atmosphere
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Answer:

D - all of the above

Explanation:

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1 year ago
Rank the following 0.100 M solutions in order of increasing H3O+ concentration:
Inessa05 [86]

Answer:

HCN < HOCl < HF  

Explanation:

The larger the Kₐ value, the stronger the acid.

6.2 × 10⁻¹⁰ < 4.0 × 10⁻⁸ < 6.3 × 10⁻⁴

   HCN      <     HOCl    <      HF

 weakest       stronger    strongest

5 0
3 years ago
The equilibrium constant for the chemical equation is Kp = 5.23 at 191 °C. Calculate the value of the Kc for the reaction at 191
Lapatulllka [165]
To convert from Kp to Kc, you need this formula---> Kp= Kc (RT)^Δn, where Δn= gas moles of product- gas moles of reactants. since you did not give a reaction formula, I can't calculate Δn. but all once you find it out. just plug it. 

Kp= Kc (RT)^Δn------------------> Kc= Kp/[(RT)^Δn]
 Kp= 5.23
R= 0.0821
T= 191 C= 464 K
Δn= ?

Kc= 5.23/ (0.0821 x 464)^Δn= ???

7 0
3 years ago
Many enzymes are inhibited irreversibly by heavy metal ions such as Hg2+ , Cu2+ , or Ag+ , which can react with essential sulfhy
3241004551 [841]

Answer:

The minimum molecular weight of the enzyme is 29.82 g/mol

Explanation:

<u>Step 1:</u> Given data

The volume of the solution = 10 ml = 10*10^-3L

Molarity of the solution = 1.3 mg/ml

moles of AgNO3 added = 0.436 µmol = 0.436 * 10^-3 mmol

<u>Step 2:</u> Calculate the mass

Density = mass/ volume

1.3mg/mL = mass/ 10.0 mL

mass = 1.3mg/mL *10.0 mL = 13mg

<u>Step 3:</u> Calculate minimum molecular weight

Molecular weight = mass of the enzyme / number of moles

Molecular weight of the enzyme = 13mg/ 0.436 * 10^-3 mmol

Molecular weight = 29.82 g/mole

The minimum molecular weight of the enzyme is 29.82 g/mol

7 0
3 years ago
Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
steposvetlana [31]
Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
      = (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
      = 176.15 kJ - 84.78 kJ = 91.38 kJ 
 





 
6 0
3 years ago
Read 2 more answers
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