The amount of heat lost by the copper is 2402.4 J.
To Calculate the amount of heat lost, we use the formula below.
<h3>Formula:</h3>
- Q = cm(t₂-t₁)................. Equation 1
<h3>Where:</h3>
- Q = Amount of heat lost
- c = specific heat capacity of copper
- m = mass of copper
- t₂ = Final temperature
- t₁ = Initial temperature
From the question,
<h3>Given:</h3>
- m = 78 g
- c = 0.385 J/g°C
- t₂ = 120°C
- t₁ = 40°C
Substitute these values into equation 1.
- Q = 78(0.385)(120-40)
- Q = 2402.4 J
Hence, The heat lost by the copper is 2402.4 J
Learn more about heat here: brainly.com/question/13439286
Water, lower, and I'm not too sure for the third one... sorry.
1. The <span>student with a measurement that might be in centimeters is A. Bill.
2. C</span><span>entimeters in 0.05 kilometers is </span>C. 5,000
solution:
0.05 km x (1000 meters/ 1 km)
= 50 meters x (100 cm/ 1 meter)
=5000 cm
Answer:
0.482 ×10²³ molecules
Explanation:
Given data:
Volume of gas = 2.5 L
Temperature of gas = 50°C (50+273 = 323 k)
Pressure of gas = 650 mmHg (650/760 =0.86 atm)
Molecules of N₂= ?
Solution:
PV= nRT
n = PV/RT
n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k
n = 2.15 atm. L /26.52 atm. mol⁻¹.L
n = 0.08 mol
Number of moles of N₂ are 0.08 mol.
Number of molecules:
one mole = 6.022 ×10²³ molecules
0.08×6.022 ×10²³ = 0.482 ×10²³ molecules
Hydrogen gas(H2) has a molar mass of 2 g. Molar mass of a substance is defined as the mass of 1 mole of that substance. And by 1 mole it is meant a collection of 6.022*10^23 particles of that substance.
So number of moles of H2 are 0.5 in this case. And thus it means there are (6.022*10^23)*0.5 particles( here they are molecules) in 1g of H2.
