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jasenka [17]
3 years ago
6

In what way is Model A better than Model B? Model A shows the types of elements in the compound, but Model B does not. Model A s

hows the total number of atoms in the molecule, but Model B does not. Model A shows the three-dimensional shape of the molecule, but Model B does not. Model A shows the number of atoms of each element in the molecule, but Model B does no
Chemistry
2 answers:
ArbitrLikvidat [17]3 years ago
7 0

Answer:the answer is c babes

Explanation:

I hope I could help y’all

Have a nice day

Or whatever day u want LMA0 it’s not up to me. Ight peace loves

telo118 [61]3 years ago
6 0

Answer:

the correct answer is B

Explanation:

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Balance the equation, complete ionic equation, and net ionic equation for these 3:
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Answer:

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Predict the method of extraction used to obtain calcium from its ore
Norma-Jean [14]

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Reactivity and extraction method

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AVprozaik [17]

Answer: The pressure of the He is 2.97 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{N_2}+p_{O_2}+p_{He}.

Given : p_{total} =total pressure of gases = 6.50 atm

p_{N_2} = partial pressure of Nitrogen = 1.23 atm

p_{O_2} = partial pressure of oxygen = 2.3 atm

p_{He} = partial pressure of Helium = ?

putting in the values we get:

6.50atm=1.23atm+2.3atm+p_{He}  

p_{He}=2.97atm

The pressure of the He is 2.97 atm

3 0
3 years ago
What evidence did Alfred Wagner have to support his idea of continental drift
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Alfred Wagner's evidence began at the simplest form that the continents appeared to<em> fit</em> together like pieces to a puzzle. It wasn't only that though. The evidence showed that the same rocks and fossils existed on separate continents - the same continents that if pieced together would be connected. 
8 0
4 years ago
What is the change in enthalpy for the following reaction? 
Tju [1.3M]

The given chemical reaction is:

2H_{2}O_{2}(aq)---> 2H_{2}O(l)+O_{2}(g)

The standard heats of formation of H_{2}O and H_{2}O_{2} are:

ΔH_{f}^{0}(H_{2}O) = -285.8kJ/mol[/tex]

ΔH_{f}^{0}(H_{2}O_{2}) = -187.6 kJ/mol[/tex]

Calculating the change in heat:

ΔH^{0}_{reaction)=∑ΔH_{f}^{0}(products)-∑ΔH_{f}^{0}(reactants)

                         = [{2 * (-285.8 kJ/mol)} -{2*(-187.6 kJ/mol)}]

                          = -196.4 kJ/mol

Therefore, the change in enthalpy for the given reaction is -196.4 kJ/mol



7 0
4 years ago
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