In the gas egquation PV=RT, V stands for volume of

F a sample of butene (C4H8) that has a mass of 136.6 g is combusted in excess oxygen, what is the mass of CO2 that is produced?

alukav5142 [94]

The balanced chemical reaction will be:

C4H8 + 6 O2 --> 4 CO2 + 4 H2O

We are given the amount of butene being combusted. This will be our starting point.

136.6 g C4H8 (1 mol C4H8/ 56.11 g C4H8) (4 mol CO2/1 mol <span>C4H8</span>) ( 44.01 g CO2/ 1 mol CO2) = 428.6 g CO2

7 0

3 years ago

Read 2 more answers

( Cooking Popcorn using a mircowave Burning yourself by touching burning water the handle of a pot becoming to hot to touch as i

mihalych1998 [28]

Conduction - touching hot pot
Convection - oven cycling warm air
Conduction - touching a warm coffee mug
Heat from a fire - radiation
Heat from the sun to solar panel - radiation
Warm water rising - convection

3 0

3 years ago

Choose all the answers that apply.

Stolb23 [73]

Answer:

the first statement

Explanation:

hope this helps

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6 0

3 years ago

Air at 293 K and 750 mm Hg pressure has a relative humidity of 80%. What is its percent humidity? The vapour pressure of water a

Mekhanik [1.2K]

Answer : The correct option is, (c) 79.62

Explanation :

The formula used for percent humidity is:

$\text{Percent humidity}=\text{Relative humidity}\times \frac{p-p^o_v}{p-p_v}\times 100$ ..........(1)

The formula used for relative humidity is:

$\text{Relative humidity}=\frac{p_v}{p^o_v}$ ...........(2)

where,

$p_v$ = partial pressure of water vapor

$p^o_v$ = vapor pressure of water

p = total pressure

First we have to calculate the partial pressure of water vapor by using equation 2.

Given:

$p=750mmHg$

$p^o_v=17.5mmHg$

Relative humidity = 80 % = 0.80

Now put all the given values in equation 2, we get:

$0.80=\frac{p_v}{17.5mmHg}$

$p_v=14mmHg$

Now we have to calculate the percent humidity by using equation 1.

$\text{Percent humidity}=0.80\times \frac{750-17.5}{750-14}\times 100$

$\text{Percent humidity}=79.62\%$

Therefore, the percent humidity is 79.62 %

4 0

4 years ago

What is the total number of outer (valence) electrons in carbon dioxide, co2? answer?

Anuta_ua [19.1K]

Carbon dioxide has a total of 16 valence electrons.

1. To determine the number of valence electrons of carbon dioxide (CO2), first determine the number of valence electrons of each of the elements in the molecule.

a. We have 1 carbon (C) molecule, and 2 oxygen (O) molecules.

b. The carbon molecule has 4 valence electrons and each oxygen molecule has 6 oxygen molecules.

2. Add up the valence electrons of each of the elements

4 + (2 x 6) = 16
(from C) (2 oxygen molecules, with 6 valence electrons each)

Thus, CO2 has a total of 16 valence electrons.

The number of valence electrons can be more clearly seen from the Lewis structure of the CO2 in the figure below (Source: http://chemistry.tutorvista.com/inorganic-chemistry/bonding-electrons.html). The the dots surrounding the letters represent the valence electrons.

8 0

3 years ago