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tamaranim1 [39]
3 years ago
7

Which metal works best to displace hydrogens from acid?

Physics
1 answer:
egoroff_w [7]3 years ago
5 0
Lead is answer i think
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Two stars of masses M and 6M are separated by a distance D. Determine the distance (measured from M) to a point at which the net
kotykmax [81]

Answer:

0.29D

Explanation:

Given that

F = G M m / r2

F = GM(6m) / (D-r)2

G Mm/r2 = GM(6m) / (D-r)2

1/r2 = 6 / (D-r)2

r = D / (Ö6 + 1)

r = 0.29 D

See diagram in attached file

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2 years ago
Which tool would you use to measure the amount of rainfall
mariarad [96]
A rain gauge! Hope this helps!
3 0
3 years ago
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A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130
konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(c) W = 0J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

W=Fd      (1)

F: applied force = 130N

d: distance = 5.0m

W=(130N)(5.0m)=650J

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

W_f=F_fd=\mu Mgd       (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

W = 0J

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

\Delta K=W_T         (3)

You calculate the total work:

W_T=Fd-F_fd=(F-F_f)d     (4)

F: applied force = 130N

Ff: friction force

d: distance = 5.00m

The friction force is:

F_f=(0.300)(36.0kg)(9.8m/s^2)=105.84N

Next, you replace the values of all parameters in the equation (4):

W_T=(130N-105.84N)(5.00m)=120.80J

\Delta K=120.80J

The change in the kinetic energy of the box is 120.8J

(e) The final speed of the box is calculated by using the equation (3):

W_T=\frac{1}{2}M(v_2^2-v_1^2)       (5)

v2: final speed of the box

v1: initial speed of the box = 0 m/s

You solve the equation (5) for v2:

v_2 = \sqrt{\frac{2W_T}{M}}=\sqrt{\frac{2(120.8J)}{36.0kg}}=2.58\frac{m}{s}

The final speed of the box is 2.58m/s

5 0
3 years ago
two identical small charged spheres are a certain distance apart, and each one initially experiences an electrostatic force of m
alexdok [17]
The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.

F α Qq

If the charges are now half the initial charges: 

<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q

The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
4 0
3 years ago
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What is the longest wavelength of light that will emit electrons from a metal whose work function is?
alexdok [17]
 Best Answer:<span>  </span><span>hf = work function + KE 
However if you are looking at the max wavelength (or threshold frequency) then there will only be just enough energy for the photoelectrons to be liberated, hence their KE will be 0. 
So hf = work function 
convert eV to joules, 2.4 x (1.6 x 10^-19) = 3.84 x 10^-19 
therefore, hf = 3.84 x 10^-19 
f = 3.84 x 10^-19 / planck's constant which is 6.63 x 10^-34 
f = 5.79 x 10^14 Hz 
c = frequency x wavelength, 
wavelength = speed of light/frequency 
= (3x10^8)/(5.79x10^14) 
=5.18 x 10^-7 metres</span>
6 0
3 years ago
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