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Brut [27]
2 years ago
7

I know the acceleration due to gravity (ie 9.8 m/s2) will have a negative sign when falling down, a positive one when going up.

Physics
1 answer:
rewona [7]2 years ago
6 0

Answer:

Yes

Explanation:

Accerelation is measured by change in velocity. So naturally, if an object is slowing down, its velocity is decreasing so acceleration is negative. If it is speeding up velocity is increasing so positive acceleration.

(Velocity final - Velocity initial)/t

Note that this does not apply only to gravity, but to all linear accelerations

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What is the density of a substance that has a mass of 453g and a volume of 224mL?
Mrrafil [7]
Density is mass per unit volume. In this case, the unit is g/ml
Mass=453g                              ρ=453g/224ml
Volume=224ml                         ρ=2.022g/ml(rounded to nearest hundredth)
Density=?
ρ=mass/volume
Therefore the density of the substance is 2.022g/ml

6 0
3 years ago
What is the magnetic force of a 30m long power line that carries a current of 50A. The magnetic field runs perpendicular to the
Ne4ueva [31]

Answer:

F=BILsin90 when perpendicular sin90 =1 30T x50x30 so you can get 45000N

8 0
3 years ago
Which actions are examples of conserving resources? Check all that apply.
uysha [10]

Answer:

1st, 2nd, and 4th

Explanation:

1st conserves gasoline/petroleum

2nd conserves electricity

4th conserves paper

6 0
3 years ago
Read 2 more answers
Knowledge of projectile motion might help you aim a basketball when you throw it so it is more likely to go into the basket. tru
8_murik_8 [283]

Answer: True.

Explanation:

You would be able to visualize the basketballs height going up and when it sinks down into the hoop.

5 0
2 years ago
An archer puts a 0.30 kg arrow to the bowstring. An average force of 201 N is exerted to draw the string back 1.3 m.a. Assuming
Vlad [161]

Answer:

Explanation:

Given

mass of archer m=0.3\ kg

Average force F_{avg}=201\ N

extension in arrow x=1.3\ m

Work done to stretch the bow with arrow

W=F\cdot x

W=201\times 1.3=261.3\ m

This work done is converted into kinetic Energy of arrow

W=\frac{1}{2}mv^2

where v= velocity of arrow

261.3=\frac{1}{2}\times 0.3\times v^2

v=\sqrt{1742}

v=41.73\ m/s

(b)if arrow is thrown vertically upward then this energy is converted to Potential energy

W=mgh

261.3=0.3\times 9.8\times h

h=\frac{261.3}{0.3\times 9.8}

h=88.87\ m

   

4 0
3 years ago
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