You run 0.5 miles every 3 minutes => 1 mile every 6 minutes. Your friend runs 2 miles every 14 minutes => 1 mile every 7 minutes. You run a whole number of miles every number of minutes that is a multiple of 6. Your freind runs a whole number of miles every number of minutes that is a multiple of 7 Then the least possible number of miles that you both run to end at the same time is the least common factor of 7 and 6 minutes. This is 7 * 6 = 42 minutes. You will have run 42 min / (6 miles/min) = 7 miles, and your friend will have run 42 min / (7 miles/min) = 6 miles
I think it would be 5/11
If I'm wrong plz don't report me
Have A Good Day
Answer:
The value for the original mean = 32
Step-by-step explanation:
Here, we want to calculate the original value of the mean.
Let the number of samples be n
Mathematically;
mean = Total value/n
Now, we added 8 to each of values; total value added = 8 * n = 8n
Now, for the new mean of 40; we have
(Total value + 8n)/n = 40
Total value + 8n = 40n
Total value = 40n -8n
Total value = 32n
kindly recall from the beginning of the solution;
mean = Total value/n
mean = 32n/n
mean = 32
So the original value of the mean is 32
3x - 5 = -26
<u>step 1:</u>
subtract +5 on each side because you have to do the inverse operation
<u>step 2:</u>
3x= -21
<u>step 3:</u>
now divide 3 on each side
the answer is -7
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Hope this helped!
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<em>TheOneAndOnlyLara~</em>
Answer:
The 2 numbers are 14 and 17.
Step-by-step explanation:
Let the 2 numbers be x and y.
x + 11 = 2y
x - 2y = -11...............A
y +20 = 2x
2x - y = 20 ...............B
Multiply equation A by -2:
-2x + 4y = 22............C
Adding B and C :-
3y = 42
y = 14.
Substitute y = 14 in equation A:
x - 2(14) = -11
x = -11 + 28
x = 17.
