Answer:
I believe the answer is
Explanation:
I may be incorrect because I used to do this a long time ago but I believe I am correct
HOPE THIS HELPS!
(:
Please see attached picture for answer an explanation.
Answer:
the buoyant force acting on the ice cube is 0.119 N
Explanation:
given,
volume of ice cube = 15 cm³ = 15 × 10⁻⁶ m³
density of ice cube = 917 kg/m³
density of ethyl alcohol = 811 kg/m³
buoyant force = ?
The density of ice is more than ethyl alcohol hence it will sink.
buoyant force acting on the ice cube = ρ V g
= 811 × 15 × 10⁻⁶ × 9.81
=0.119 N
so, the buoyant force acting on the ice cube is 0.119 N
Answer:
What does this mean i don't get you??
Find the velocity of the object after one second.
v = vo + at
v = (0 m/s) + (9.8 m/s^2)(1 s)
v = 9.8 m/s
Now, using that, you can find the displacement in that one second between 1 and 2.
d = vot + (1/2)at^2
d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2
d = 14.7 m
