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marusya05 [52]
2 years ago
9

Source localization in ocean acoustics is posed as a machine learning problem in which data-driven methods learn source ranges d

irectly from observed acoustic data
Physics
1 answer:
Temka [501]2 years ago
6 0

Source localization in ocean acoustics is posed as a machine learning problem in which data-driven methods learn source ranges directly from observed acoustic data: True.

<h3>What is machine learning?</h3>

Machine learning (ML) is also known as artificial intelligence (AI) and it can be defined as a subfield in computer science which typically focuses on the use of computer algorithms, data-driven techniques (methods) and technologies to develop a smart computer-controlled robot that has the ability to automatically perform and manage tasks that are exclusively meant for humans or solved by using human intelligence.

In Machine learning (ML), data-driven techniques (methods) are used to learn source ranges directly from observed acoustic data in a bid to proffer solutions to source localization in ocean acoustics.

In conclusion, a normalized sample covariance matrix (SCM) is constructed and used as the input, especially after pre-processing the pressure that's received by a vertical linear array in Machine learning (ML).

Read more on machine learning here: brainly.com/question/25523571

#SPJ1

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A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
e-lub [12.9K]

Answer:

The direction of the car’s change in linear momentum is 149.04° West of North

Explanation:

Momentum is defined as the product of mass of a body and its velocity

Momentum = mass × velocity

Change in Momentum = mass × change in velocity

∆P = m∆v

∆P = m(v-u)

Given m = 1500kg

v = 25m/s

u = 15m/s

∆P = 1500(25-15)

∆P = 1500×10

∆P = 15,000kgm/s

Since the car first travels due East i.e +x direction

x = 25m/s

Travelling due south is negative y direction

y = -15m/s

Direction of the car change

θ = tan^-1(y/x)

θ = tan^-1(-15/25)

θ = tan^-1(-0.6)

θ = -30.96°

Since tan is negative in the second quadrant

θ = 180-30.96

θ = 149.04°

The direction of the car’s change in linear momentum is 149.04° West of North

5 0
4 years ago
The lower the temperature of the solvent, the faster the solute will dissolve. True False
denis23 [38]

Answer:

false.

Explanation:

Since temperature and kinetic energy of molecules are proportional, the more we increase the temperature of the solvent, the faster the solute will dissolve.

This increase of kinetic energy allows the solvent molecules to more effective break apart the solvent molecules that are held together by intermolecular forces.

4 0
3 years ago
Consider the direction field of the differential equation dy/dx = x(y − 6)2 − 4, but do not use technology to obtain it. Describ
Alona [7]

Answer:

The slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.

Explanation:

Given;

The slope, dy/dx = 2x(y-6) - 4

2x(y-6) - 4 = 2xy - 12x - 4, divide through by 'x'

dy/dx = 2y -12 - 4/x

The slopes of the linear elements on the lines, x =0, y = 5, y = 6, y = 7.

At x = 0, and y = 5

dy/dx = 2y -12 - 4/x

dy/dx = 2(5) - 12 = -2

At x = 0, and y = 6

dy/dx = 2y -12 - 4/x

dy/dx = 2(6) - 12 = 0

At x = 0, and y = 7

= 2y -12 - 4/x

dy/dx = 2(7) - 12 = 2

Therefore, the slopes shows that the direction of the field is from -2 to +2, with three point charges, q₁, q₂ and q₃ at -2, 0 and +2 respectively.

5 0
3 years ago
The Atoms Family
ioda
What question are you asking?
4 0
3 years ago
Compare the characteristics of 4d orbitals and 3d orbitals and compared the following sentences. Check all that apply
charle [14.2K]

Answer :

<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>

<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>

Explanation :

As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.

Hence, 4d orbitals would be larger in size than 3d orbitals.

Number of nodes is any orbital is n - 1 where, n is principal quantum number.

So, number of orbital in 4d is 3.

And number of orbital in 3d is 2.

So, options (b) and (e) are correct.

8 0
3 years ago
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