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3 years ago

What 2 kinds of substances does convection occur ?

Physics

1 answer:

ch4aika [34]3 years ago

4 0

Liquids and Gases

Explanation:

Convection is a form of heat transfer that is predominant in liquids and gaseous substances. This form of heat transfer is driven by density differences between gases and liquids.

Convection involves the actual movement of the particles of a medium.
Boiling of food is clinical example of convection in liquids. Hot part of the food in contact with the heat source becomes less dense and more buoyant. They rise to the top of the medium and are replace by the denser and colder part of the food.
Land and sea breeze is an example of convection in gases. The land warms the air around it during the day. It is hotter and less dense. The air mass moves to replace the ones on the sea where the air is relatively cold due to high specific heat capacity of water.
The reverse process occurs at night.

Learn more:

Heat transfer from the sun brainly.com/question/1140127

#learnwithBrainly

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A 5-m steel beam is lowered by means of two cables unwinding at the same speed from overhead cranes. As the beam approaches the

ArbitrLikvidat [17]

Answer:

a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)

b) The acceleration of point A is 3.25 m/s²

The acceleration of point E is 0.75 m/s²

Explanation:

a) The relative acceleration of B with respect to D is equal:

$a_{B} =a_{D} +(a_{B/D} )_{n} +(a_{B/D} )_{t}$

Where

aB = absolute acceleration of point B = 2.5 j (m/s²)

aD = absolute acceleration of point D = 1.5 j (m/s²)

(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam

(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)

$a_{B} =a_{D} +(a_{B/D} )_{t}$

$2.5j=1.5j +(a_{B/D} )_{t}\\(a_{B/D} )_{t}=j=1m/s^{2}$

We have that

(aB/D)t = BDα

Where α = acceleration of the beam

BDα = 1 m/s²

Where

BD = 2

$2\alpha =1\\\alpha =0.5rad/s^{2}CW$

b) The acceleration of point A is:

$a_{A} =a_{D} +(a_{A/D} )_{t}$

(aA/D)t = ADαj

$a_{A} =a_{D} +AD\alpha j\\a_{A}=1.5j+(3.5*0.5)j\\a_{A}=3.25jm/s^{2}$

The acceleration of point E is:

(aE/D)t = -EDαj

$a_{E} =a_{D} -ED\alpha j\\a_{E}=1.5j-(1.5*0.5)j\\a_{E}=0.75jm/s^{2}$

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Answer:

They provide a source of electrons to be released by the photoelectric effect, and They provide a path through which released electrons move to form an electric current.

Explanation:

A p e x

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