Answer:
Explanation:
Initial angular velocity ω₁ = 0 , final angular velocity ω₂ = 75.9 rad /s
angle rotated = θ
= 37 x 2π
= 74 π
The formula for angular velocity
ω₂² = ω₁² + 2αθ , α is angular acceleration
75.9² = 0 + 2 α x 74 π
α = 75.9² / 2 x 74 π
= 12.396 rad / s²
Addition of 2vector gives you 1large vector quantity
Answer:
I do belive that it is B hrs cn I an gn
Answer:
1.4 m/s/s (2.s.f)
Explanation:
The formula for centripetal acceleration is:
, where v is velocity and r is the radius.
In the question we are given the information that the car has a mass of 1300kg, a velocity of 2.5m/s, and a turn radius of 8.5m which are all the values we need. Therefore we can simply substitute in the values to solve the question:
Therefore the centripetal acceleration of the car is 1.4m/s/s. (2.s.f)
Hope this helped!
Equations of the vertical launch:
Vf = Vo - gt
y = yo + Vo*t - gt^2 / 2
Here yo = 35.0m
Vo is unknown
y final = 0
t = 4.00 s
and I will approximate g to 10m/s^2
=> 0 = 35.0 + Vo * 4 - 5 * (4.00)^2 => Vo = [-35 + 5*16] / 4 = - 45 / 4 = -11.25 m/s
The negative sign is due to the fact that the initial velocity is upwards and we assumed that the direction downwards was positive when used g = 10m/s^2.
Answer: 11.25 m/s
