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3 years ago

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A child is sledding on a smooth, level patch of snow. She encounters a rocky patch and slows to a stop. Draw a motion diagram, u

sing the particle model, showing her velocity vectors.

1 answer:

Ray Of Light [21]3 years ago

4 0

Answer:

Explanation:

The diagram for child is sledding on a smooth, level patch of snow. She encounters a rocky patch and slows to a stop is shown in the attachment.

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The balloon's behavior results from a change at the electron level. What do you think might have happened while rubbing the ball

Mariulka [41]

Answer:

Explanation:

opposite charges attract each other, while rubbing the objects together they developed opposite charges which caused them to drift together

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4 years ago

A moving walkway at an airport has a speed v1 and a length L. A woman stands on the walkway as it moves from one end to the othe

bearhunter [10]

Answer:

t=L/ $V_1$

Explanation:

<u>solution:</u>

Let E be an observer, and B a second observer traveling with velocity $V_{BE}$ as measured by E. If E measures the velocity of an object A as $V_{AE}$ then B will measure A velocity as

$V_{AB}$ = $V_{AE}$ - $V_{BE}$

Applied here,

the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is

$V_{MW}$ = $V_{ME}$ - $V_{WE}$

$V_1=V_{WE}$ ,

$V_2=V_{MW}$

The time required for the woman, traveling at constant speed $V_1$ relative to the ground, to travel distance L relative to the ground is :

t=L/ $V_1$

3 0

4 years ago

A model rocket fired vertically from the ground ascends with a constant vertical acceleration of 52.7 m/s2 for 1.41 s. its fuel

olya-2409 [2.1K]

For rectilinear motions, derived formulas all based on Newton's laws of motion are formulated. The equation for acceleration is

a = (v2-v1)/t, where v2 and v1 is the final and initial velocity of the rocket. We know that at the end of 1.41 s, the rocket comes to a stop. So, v2=0. Then, we can determine v1.

-52.7 = (0-v1)/1.41
v1 = 74.31 m/s

We can use v1 for the formula of the maximum height attained by an object thrown upwards:

Hmax = v1^2/2g = (74.31^2)/(2*9.81) = 281.42 m

The maximum height attained by the model rocket is 281.42 m.

For the amount of time for the whole flight of the model rocket, there are 3 sections to this: time at constant acceleration, time when it lost fuel and reached its maximum height and the time for the free fall.

Time at constant acceleration is given to be 1.41 s. Time when it lost fuel covers the difference of the maximum height and the distance travelled at constant acceleration.

2ax=v2^2-v1^2
2(-52.7)(x) = 0^2-74.31^2
x =52.4 m (distance it covered at constant acceleration)
Then. when it travels upwards only by a force of gravity,
d = v1(t) + 1/2*a*t^2
281.42-52.386 = (0)^2+1/2*(9.81)(t^2)
t = 6.83 s (time when it lost fuel and reached its maximum height)

Lastly, for free falling objects, the equation is
t = √2y/g = √2(281.42)/9.81 = 7.57 s

Therefore, the total time= 1.41+6.83+7.57 = 15.81 s

6 0

3 years ago

A 41.0 kg child swings in a swing supported by two chains, each 2.98 m long. (a) If the tension in each chain at the lowest poin

Alex777 [14]

Answer:695.5 N

Explanation:

mass of child $m=41 kg$

Length of chain $L=2.98 m$

Tension in each chain $T=348 N$

(a)Tension at bottom point $T=348 N$

At lowest Point

$T+T-mg=\frac{mv^2}{L}$

$2T-mg=\frac{mv^2}{L}$

$2\times 348-41\times 9.8=\frac{41\times v^2}{2.98}$

$v^2=\frac{294.2\times 2.98}{41}$

$v=\sqrt{21.38}=4.62 m/s$

(b)Force exerted by Seat will be Equal to Normal reaction

$N-mg=\frac{mv^2}{L}$

$N=mg+\frac{mv^2}{L}$

$N=41\times 9.8+\frac{41\times 21.38}{2.98}$

$N=695.95 N$

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3 years ago

The redshift of the galaxies is correctly interpreted as

pickupchik [31]

Doppler shift due to random motion of galaxies ,an aging of light as gravity weakens with time ,the difference in temperature and star formation in old and new galaxies

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4 years ago

Read 2 more answers