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AysviL [449]
4 years ago
7

Hellllppppppppppp meeeee plzzzzzzz!!!!!!!!!!!!!’

Mathematics
2 answers:
adell [148]4 years ago
6 0

Answer:


Step-by-step explanation:

The third answer expresses one or more themes


MAXImum [283]4 years ago
6 0

Answer:

B I believe and if thats not correct C

Step-by-step explanation:


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Someone please help me
mezya [45]
It's B, 20in^2


So yeah!
5 0
4 years ago
Read 2 more answers
A label prints in the pediatric pharmacy
Elden [556K]

Answer:

107.14 ml of 70% dextrose and 392.86 ml of sterile water should be used.

Step-by-step explanation:

Since a label prints in the pediatric pharmacy satellite for 500 mL of dextrose 15% solution, but this concentration is not available commercially and needs to be compounded, and available in your pharmacy, you have a 1 L bag of sterile water and a 1 L bag of dextrose 70% available to compound the solution, to determine how many mLs of each are needed to make the requested solution, the following calculation must be performed:

500 x 0.15 = 75

100 x 0.70 = 70

A x 0.70 = 75

A = 75 / 0.70

A = 107.14

Therefore, 107.14 ml of 70% dextrose and 392.86 ml of sterile water should be used.

5 0
3 years ago
The temperature is 5 degrees Fahrenheit by midnight the temperature is expected to drop 15 degrees Fahrenheit What will the temp
velikii [3]
-10 degrees Fahrenheit
8 0
4 years ago
if a polyhedron has a volume of 35 cm^3 and is dilated by a factor of 5/2, what will be the volume of the dilated polyhedron? Ro
Sergio [31]

If a polyhedron has a volume of 35 cm cube and is dilated by a factor of 5/2 then the volume of dilated polyhedron will be 50.6 cm cube.

Given Volume of polyhedron=35 cm cube . Factor from which is dilated 5/2.

If the polyhedron is dilated by factor 5/2 then the volume of the polyhedron will change by the cube of that  factor because when it is dilated by factor its material also increases.

Volume =35cm^{3}

After dilation

Volume=35+(5/2)^{3}

=35+15.625

=50.625

After Rounding nearest to thousand we will get 50.6 cm^{3}.

Hence after dilation the volume which is 35 cm cube will change from 35 to 50.6cm^{3}.

Learn more about volume at brainly.com/question/463363

#SPJ10

3 0
2 years ago
in a study of red/green color blindness, 600 men and 2150 women are randomly selected and tested. Among the men, 56 have red/gre
Umnica [9.8K]

Answer:

z=13.36 (Statistic)

p_v =P(Z>13.36)\approx 0

The p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of men with red/green color blindness is significant higher than the proportion of female with red/green color blindness .

Step-by-step explanation:

1) Data given and notation

X_{MCB}=56 represent the number of men with red/green color blindness

X_{WCB}=5 represent the number of women with red/green color blindness

n_{MCB}=600 sample of male selected

n_{WCB}=600 sample of demale selected

p_{MCB}=\frac{56}{600}=0.093 represent the proportion of men with red/green color blindness

p_{WCB}=\frac{5}{2150}=0.0023 represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

p_v represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportion for men with red/green color blindness is a higher than the rate for women  , the system of hypothesis would be:

Null hypothesis:p_{MCB} \leq p_{WCB}

Alternative hypothesis:p_{MCB} > \mu_{WCB}

We need to apply a z test to compare proportions, and the statistic is given by:

t=\frac{p_{MCB}-p_{WCB}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{MCB}}+\frac{1}{n_{WCB}})}}   (1)

Where \hat p=\frac{X_{MCB}+X_{WCB}}{n_{MCB}+n_{WCB}}=\frac{56+5}{600+2150}=0.0221

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

z=\frac{0.093-0.0023}{\sqrt{0.0221(1-0.0221)(\frac{1}{600}+\frac{1}{2150})}}=13.36  

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:

p_v =P(Z>13.36)\approx 0

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion of men with red/green color blindness is significant higher than the proportion of female with red/green color blindness .

4 0
3 years ago
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