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ratelena [41]
3 years ago
12

Please help if you know how to do Similarity in Geometry!!

Mathematics
1 answer:
Marizza181 [45]3 years ago
3 0

2. TU, UV and TV are mid-segments

3. Definition of mid-segment

4. Division property of equality

6. SSS similarity theorem

Solution:

Step 1: Given

T is the midpoint of QR.

U is the midpoint of QS.

V is the midpoint of RS.

Step 2: Mid-segments connects midpoints of opposite sides.

TU, UV and TV are mid-segments.

Step 3: By definition of mid-segment

A triangle mid-segment is parallel to the third side of the triangle and is half of the length of the third side.

T U=\frac{1}{2} R S, {U V}=\frac{1}{2} {Q} R and V T=\frac{1}{2} S Q

Step 4: By division property of equality

Divide first segment by RS, second segment by QR and third segment by SQ.

$\frac{T U}{R S}=\frac{1}{2}, \ \frac{U V}{Q R}=\frac{1}{2},  \ \frac{V T}{S Q}=\frac{1}{2}

Step 5: By transitive property

$\frac{T U}{R S}=\frac{U V}{Q R}=\frac{V T}{S Q}

Step 6: From the above steps, the sides of the triangle are congruent.

By SSS similarity theorem,

\Delta \text { QRS } \sim \Delta \text { VUT }

Hence proved.

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vladimir1956 [14]

Answer:

The pairs ( 1 , 2 ) and ( 2 , 1 ) are not equal because their respective elements are not equal.

Step-by-step explanation:

The pair of elements which are in specific order is called an ordered pair. The pair ( 1 , 2 ) is not same as the pair ( 2 , 1 ). In the pair ( 1 , 2 ) 1 is in the first position and 2 is in the second position. In the pair ( 2 , 1 ), 2 is in the first position and 1 is in the second position.

Two ordered pairs ( a , b ) and (c , d ) are said to be equal if a = c and b = d. We write ( a , b ) = ( c , d ).

Hope I helped!

Best regards!!

8 0
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