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4 years ago

When can stem call produce new muscle

1 answer:

3 0

When the body recovers from a muscular injury, it relies on a kind of stem cell called a muscle satellite cell. These cells accomplish what surgical intervention can't: They differentiate to form new muscle fibers, and fuse with existing muscle to repair an injury.

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A clothing store has sensors that track how many people enter the store and cash registers that track how many purchases people

Ksivusya [100]

This information is valuable because Managers can use this customer data each month to figure out whether a larger or smaller percentage of visitors are buying clothes there.

<h3>What is the percentage of a number?</h3>

It is the relative value that represents the hundredth part of any number for example 2% of any number represents, 2 multiplied by the 1/100th of that number.

A clothes business contains sensors that count the number of customers entering the store and cash registers that count the number of transactions made daily.

Thus, data is useful because Managers may use it to determine if a greater or lesser proportion of customers are purchasing clothing each month. Therefore the correct answer is option A.

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8 0

1 year ago

Which type of bond exists between an atom of fluorine and an atom of carbon?

babymother [125]

Should be a Polar-Covalent bond.

6 0

3 years ago

Read 2 more answers

12. Suppose a person uses a mechanical iack to lift half the weight of a car with a

Likurg_2 [28]

a) The force that must be applied is 73.5 N

b) The actual efficiency is 82 %

Explanation:

Since the jack is 100% efficient, all the input work is converted into output work. So we can write:

$W_{in} = W_{out}\\F_{in} d_{in} = F_{out} d_{out}$

where:

$F_{in}$ is the input force applied on the jack

$d_{in}$ is the arm of the input force

$F_{out}$ is the output force applied on the jack

$d_{out}$ is the arm of the output force

Here we have:

$F_{out}=\frac{mg}{2}= \frac{(1200 kg)(9.8 m/s^2)}{2}=5880 N$ is the output force (half the weight of the car)

$d_{in} = 40.0 cm = 0.40 m$ is the arm of the input force

$d_{out} = 5.0 mm = 0.005 m$ is the arm of the output force

Solving for $F_{in}$ , we find the force that must be applied in input to lift the car:

$F_{in} = \frac{F_{out}d_{out}}{d_{in}}=\frac{(5880)(0.005)}{0.40}=73.5 N$

The efficiency of the jack is given by the ratio between the output work and the input work:

$\eta = \frac{W_{out}}{W_{in}}=\frac{F_{out}d_{out}}{F_{in}d_{in}}$

where we have:

$F_{out}=5880 N$ is the output force (half the weight of the car)

$d_{in} = 40.0 cm = 0.40 m$ is the arm of the input force

$d_{out} = 5.0 mm = 0.005 m$ is the arm of the output force

Here we are told that the input force this time is

$F_{in}=90.0N$

Substituting into the equation, we find the new efficiency of the jack:

$\eta = \frac{(5880)(0.005)}{(90.0)(0.40)}=0.82$

Which means an efficiency of 82%.

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8 0

4 years ago

What is inside a black hole

spin [16.1K]

Answer:

At the center of a black hole, it is often postulated there is something called a gravitational singularity, or singularity. This is where gravity and density are infinite and space-time extends into infinity Explanation Explanation:

7 0

3 years ago

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The Great Sandini is a 60 kg circus performer who is shotfrom a cannon (actually a spring gun). You don't find many men ofhis ca

d1i1m1o1n [39]

Answer:

V=15.3 m/s

Explanation:

To solve this problem, we have to use the energy conservation theorem:

$U_e+K_i+U_{gi}+W_{friction}=K_f+U_{gf}$