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goblinko [34]
1 year ago
5

A clothing store has sensors that track how many people enter the store and cash registers that track how many purchases people

make each day. Why is this information valuable?
A.
Managers can use this customer data each month to figure out whether a larger or smaller percentage of visitors are buying clothes there.

B.
Managers can use this customer data each month to find out whether the store is doing as well as other clothing stores in the area.

C.
Managers can use this network each month to find out whether store employees are keeping the store clean and organized.

D.
Managers can use this network each month to find out when the number of purchases becomes larger than the number of visitors.
Physics
1 answer:
Ksivusya [100]1 year ago
8 0

This information is valuable because Managers can use this customer data each month to figure out whether a larger or smaller percentage of visitors are buying clothes there.

<h3>What is the percentage of a number?</h3>

It is the relative value that represents the hundredth part of any number for example 2% of any number represents, 2 multiplied by the 1/100th of that number.

A clothes business contains sensors that count the number of customers entering the store and cash registers that count the number of transactions made daily.

Thus, data is useful because Managers may use it to determine if a greater or lesser proportion of customers are purchasing clothing each month. Therefore the correct answer is option A.

Learn more about the percentage here,

brainly.com/question/24159063

#SPJ1

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marishachu [46]

Answer:

a) the magnitude of the force is

F= Q(\frac{kqs}{r^3}) and where k = 1/4πε₀

F = Qqs/4πε₀r³

b)  the magnitude of the torque on the dipole

τ = Qqs/4πε₀r²

Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

where k = 1/4πε₀

the expression of the electric field due to dipole at a distance r is

E(r) = \frac{kp}{r^{3} } , where p = q × s

E(r) = \frac{kqs}{r^{3} } where r>>s

a) find the magnitude of force due to the dipole

F=QE

F= Q(\frac{kqs}{r^3})

where k = 1/4πε₀

F = Qqs/4πε₀r³

b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

τ = F sinθ × s

θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

8 0
3 years ago
Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructi
pochemuha

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NO ONE WILL HELP, PLEASE PLEASE HELP, I HAVE AN HOUR TO GET 4 PAGES DONE! Find the average speed of a marble that takes 6 second
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Suppose that a stray neutron with an initial speed of 1.4 x 107 m/s is just barely captured by a nucleus with diameter d = 1.0 X
son4ous [18]

Answer:

F=16.366N

Explanation:

Given data

Initial velocity of neutron v₀=1.4×10⁷m/s

Diameter of nucleus d=1×10⁻¹⁴m

Mass of neutron m=1.67×10⁻²⁷kg

The acceleration of neutron is given from equation :

v^{2}=v_{o}^{2}+2ad\\   where\\v=0\\So\\a=\frac{v^{2}-v_{o}^{2}   }{2d}\\ a=\frac{-v_{o}^{2}}{2d}\\ a=\frac{-(1.4*10^{7}m/s )^{2}}{2(1.0*10^{-14} m)}\\a=-9.81*10^{27}m/s^{2}

So its magnitude is a=9.81×10²⁷m/s²

To find magnitude of force we use Newtons second law of motion

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F=ma\\F=(1.67*10^{-27} kg)(9.81*10^{27}m/s^{2}  )\\F=16.366N

6 0
4 years ago
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Answer:

1.20Nm

Explanation:

Given data

Force= 53.5N

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Torque= 53.5*0.0225

Torque= 1.20Nm

Hence the toque produced is  1.20Nm

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3 years ago
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