Answer:
2.23 Hz
Explanation:
From the attached diagram below; there exists a diagrammatic representation of the equilibrium position of the cylinder.
The equilibrium position of the spring is expressed as:
mg = K
where;
m = mass of the object
g = acceleration due to gravity
K = spring constant
= static deflection of the string
Given that:
m = 30 kg
g = 9.81 m/s²
= 50 mm = 50 ×
= 0.05 m
Then;
From here; let us find the angular velocity which will be needed to determine the natural frequency aftewards.
The angular velocity of the cylinder can be expressed by the formula:
Finally; the natural frequency can be calculated by using the equation
= 2.229305729
≅ 2.23 Hz
Thus; the resulting natural frequency of the vertical vibration of the cylinder = 2.23 Hz
Answer:
12.6332454263 m/s
Explanation:
m = Mass of car
v = Velocity of the car
= Coefficient of static friction = 0.638
g = Acceleration due to gravity = 9.81 m/s²
r = Radius of turn = 25.5 m
When the car is on the verge of sliding we have the force equation
The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s
Any of three muscles in each buttock that move the thigh, the largest of which is the gluteus maximus.
Answer:
2.55 Hz
Explanation:
frequency = Speed of wave / wavelength
= 21.2 / 8.3
= 2.55 Hz
<span>An atom’s emission of light with a specific amount of energy confirms that </span><span>electrons emit and absorb energy based on their position around the nucleus.
The light emitted from an electron is a result of the electron's quantum jumps/leaps ( atomic electron transitions ) to and from different energy levels.</span>