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Ivanshal [37]
3 years ago
8

Use the number line given to choose the best answer for the question. What value does point P represent on the number line shown

below?
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
5 0

Its -3



Mark me brainliest now :3

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Guys i really really need help please help me with this assignment its due today -'_'-
Tasya [4]

Answer:

Monday: 5x + 14

Tuesday: Average is about 55.77 and Median is 56

Step-by-step explanation:

To combine like terms means to add or subtract the terms with similar variables. So I did as such to find the answer.

24 - 10 = 14 and 7x - 2x = 5x

The average is found by dividing the sum of all values in the list by the number of list options. The median is the value found in the middle of the list.

4 0
3 years ago
5 plus 5 equals 10 ......................................
Maru [420]

Answer:

yes 5+5=10 any problem

6 0
2 years ago
Read 2 more answers
Evaluate the expression when a=3, b=2, and c=12
dimaraw [331]

Answer:

Step-by-step explanation:

6 + a

Putting value of a

6 + 3 = 9

5b

Putting value of b

5(2) = 10

C - 1

Putting value of c

12 - 1 = 11

5 0
3 years ago
What is the average rate of change for the line shown in the graph
kompoz [17]

Answer:

The average rate of change is 10.

Step-by-step explanation:

Since the average rate of change is the slope of a line, you'd solve this problem by finding the slope.

First, you can start by using the \frac{y_2-y_1}{x_2-x_1} method.

Plug in the points (0,10) and (1,20).

\frac{20-10}{1-0} =\frac{10}{1} =10

Therefore your answer is 10.

Hope this helped!

6 0
2 years ago
Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh
Vedmedyk [2.9K]

Answer:

Increasing: x and x>1.

Decreasing: -1

Step-by-step explanation:

We have been given a function f(x)=x^3-3x+4. We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

Let us find derivative of our given function.

f'(x)=\frac{d}{dx}(x^3)-\frac{d}{dx}(3x)+\frac{d}{dx}(4)

f'(x)=3x^{3-1}-3+0

f'(x)=3x^{2}-3

Let us equate derivative with 0 as find critical points as:

0=3x^{2}-3

3x^{2}=3

Divide both sides by 3:

x^{2}=1

Now we will take square-root of both sides as:

\sqrt{x^{2}}=\pm\sqrt{1}

x=\pm 1

x=-1,1

We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (-\infty, -1) \text{ or } x.

Now we will check 0 for 2nd interval.

f'(0)=3(0)^{2}-3=0-3=-3

Since -3 is less than 0, therefore, function is decreasing on interval (-1,1) \text{ or } -1.

We will check 2 from our 3rd interval.

f'(2)=3(2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (1,\infty) \text{ or } x>1.

6 0
3 years ago
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