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artcher [175]
3 years ago
12

What is one way to increase the amplitude of a wave in a medium

Physics
1 answer:
vovikov84 [41]3 years ago
3 0

supply it with more energy. one way to do is to produce vibrations in the same frequency as the wave. This would cause resonance leading to higher amplitude
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How far apart are the fringes in the center of the pattern on a screen 4.3 m away? Express your answer to two significant figure
attashe74 [19]

Answer:

d = \frac{nLembda}{sin(theta)}

Explanation:

This comes from diffrection pattern equation used to locate fringe pattern, i will explain every variable in it here.

n = order of fringe = 0 1 2 3 .. and negative integars as well.

d is sacing between slits.

Theta = angle at which light-Ray is directed towards fringe.

It appears that the distance between consectice fringes would same as the distance between two slits 'd'.

therefore calculating that distance should give us the distance between two fringe patters.

Note we don't use transversal seperation distance here.

4 0
3 years ago
A 1000-kg car is slowly picking up speed as it goes around a horizontal curve whose radius is 100 m. The coefficient of static f
Snezhnost [94]

Answer:

18.5 m/s

Explanation:

On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:

\mu mg = m\frac{v^2}{r}

where

\mu is the coefficient of static friction between the tires and the road

m is the mass of the car

g is the gravitational acceleration

v is the speed of the car

r is the radius of the curve

Re-arranging the equation,

v=\sqrt{\mu gr}

And by substituting the data of the problem, we find the speed at which the car begins to skid:

v=\sqrt{(0.350)(9.8 m/s^2)(100 m)}=18.5 m/s

7 0
4 years ago
Read 2 more answers
You and a friend both leave the same restaurant to drive home. You are heading directly west at 30 miles per hour and he or she
steposvetlana [31]

Answer:

\frac{dAB}{dt} = = 50 miles/ hour

Explanation:

let A represent me and B represent my friend

A speed\frac{dOA}{dt}=30 m/hr toward west

B speed\frac{dOB}{dt} =40 m/hr toward south

after 1/2 hr

total distance cover by A =1/2 * 30 miles = 15 miles

total distance by B = 1/2*40 miles = 20 miles

now from figure

AB = \sqrt{(15^2+20^2)} = 25 miles

AB^2 =OA^2+ OB^2

Differentiate above equation

2AB\frac{dAB}{dt} = 2OA\frac{dOA}{dt} +2OB\frac{dOB}{dt}

25*\frac{dAB}{dt} = 15*30 +20*40

\frac{dAB}{dt} = \frac{1250}{25}

\frac{dAB}{dt} = = 50 miles/ hour

5 0
3 years ago
Read 2 more answers
Conclusion 1. why do engineers place tolerances on dimensions? 2. what are the three types of tolerances that appear on dimensio
Butoxors [25]

Tolerance enables the engineer to be informed when somethings requires replacement or if there is a drawback with too much war.

 

The three types of tolerances that appear on dimensioned drawings are limit, bilateral, and unilateral.

 

<span>General tolerances are normally found in the information blocks of the blueprint while a specific tolerance is noted for certain areas of the blueprint.</span>
7 0
3 years ago
It is cold and dry outside. You go down the slide and experience a small electric shock. What charge must you and slide be in or
ruslelena [56]

Answer:

c

Explanation:

the charge wants to ultimately balance out so either you or the slide gave the other electrons to balance the charges

3 0
3 years ago
Read 2 more answers
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