Answer:
the speed of the satellite is 12,880.53 km/h
Explanation:
Given;
radius of the circular orbit, r = 24,600 km
time taken to revolve around Earth, t = 12 hours
The circumference of the satellite is calculated as;
L = 2πr
L = 2π x 24,600 km
L = 49,200π km
L = 154,566.36 km
The speed of the satellite;
v = L/t
v = 154,566.36 / 12
v = 12,880.53 km/h
Therefore, the speed of the satellite is 12,880.53 km/h
Satellites are objects which orbit the planet. The natural satellite of Earth, in this case, is moon
Newton's 2nd law of motion:
Force = (mass) · (acceleration)
= (70 kg) · (4.2 m/s²)
= (70 · 4.2) kg·m/s²
= 294 newtons
"The wavelengths are getting longer, meaning the star is moving away from the observer" is the one among the following choices given in the question that this means about the length of light waves and movement of the star. The correct option among all the options that are given in the question is the fourth option or option "D".
Answer:
So, the findings will confirm Kepler's rule if for any two set of planets, if T₁²/R₁³= T₂²/R₃³ and contradict if T₁²/R₁³≠ T₂²/R₃³
Explanation:
Kepler has three laws of planetary orbit
1. The planets move around the sun in elliptical orbits with the sun at the center of the orbit.
2. The line joining the sun and the planet sweeps out equal areas in equal times.
3. The square of the period of revolution of the planet about the sun is directly proportional to the cube of its average distance from the sun.
We are going to consider the third law here
Let T be the orbital period about the sun and R be its orbital radius. From Kepler's third law, it follows that T² ∝ R³ and T²/R³ = constant for any planet.
So, the findings will confirm Kepler's rule if for any two set of planets, if T₁²/R₁³= T₂²/R₃³ and contradict if T₁²/R₁³≠ T₂²/R₃³
