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SVETLANKA909090 [29]
4 years ago
10

2 cycleists, 90 miles apart starting riding toward each other at some times one cycles twice as fast as the other if they meet 2

hrs later at what average speed is each cyclist traveling
Physics
1 answer:
svetlana [45]4 years ago
6 0

Average speed of the first car= 15 miles/hr

Average speed of the second car= 30 miles/hr

Explanations:

distance= d= 90 miles

Time= 2 hrs

let speed of first cyclist= v

speed of second cyclist= 2v

relative speed = v + 2v= 3v

using relative speed= Total distance/Total time

3v= 90/2

3 v=45

v=15 miles/hr

so speed of first cyclist= 15 miles/hr

speed of second cyclist= 2 (15)= 30 miles/hr

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artcher [175]

Answer:

<h2>24 kg m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 6 × 4

We have the final answer as

<h3>24 kg m/s</h3>

Hope this helps you

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Explanation:

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Answer:

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Explanation:

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A large blue marble of mass 3.5 g is moving to the right with a velocity of 15 cm/s. The large marble hits a small red marble of
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Explanation:

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m1 u1 + m2 u2 = m1 v1 + m2 v2

where:

m1 = 3.5 g  is the mass of the blue marble

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v1 = 5.5 cm/s is the final velocity of the blue marble

We can find the final velocity of the red marble by re-arranging the equation and solving for v2 :

v2 = 1/m²(m1 u1 + m2 u2 - m1 v1)=

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4 years ago
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