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SVETLANKA909090 [29]
3 years ago
10

2 cycleists, 90 miles apart starting riding toward each other at some times one cycles twice as fast as the other if they meet 2

hrs later at what average speed is each cyclist traveling
Physics
1 answer:
svetlana [45]3 years ago
6 0

Average speed of the first car= 15 miles/hr

Average speed of the second car= 30 miles/hr

Explanations:

distance= d= 90 miles

Time= 2 hrs

let speed of first cyclist= v

speed of second cyclist= 2v

relative speed = v + 2v= 3v

using relative speed= Total distance/Total time

3v= 90/2

3 v=45

v=15 miles/hr

so speed of first cyclist= 15 miles/hr

speed of second cyclist= 2 (15)= 30 miles/hr

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