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SVETLANKA909090 [29]
3 years ago
10

2 cycleists, 90 miles apart starting riding toward each other at some times one cycles twice as fast as the other if they meet 2

hrs later at what average speed is each cyclist traveling
Physics
1 answer:
svetlana [45]3 years ago
6 0

Average speed of the first car= 15 miles/hr

Average speed of the second car= 30 miles/hr

Explanations:

distance= d= 90 miles

Time= 2 hrs

let speed of first cyclist= v

speed of second cyclist= 2v

relative speed = v + 2v= 3v

using relative speed= Total distance/Total time

3v= 90/2

3 v=45

v=15 miles/hr

so speed of first cyclist= 15 miles/hr

speed of second cyclist= 2 (15)= 30 miles/hr

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Answer:

<em>a) 3.56 x 10^22 N</em>

<em>b) 3.56 x 10^22 N</em>

<em></em>

Explanation:

Mass of the sun M = 2 x 10^30 kg

mass of the Earth m = 6 x 10^24 kg

Distance between the sun and the Earth R = 1.5 x 10^11 m

From Newton's law,

F = \frac{GMm}{R^2}

where F is the gravitational force between the sun and the Earth

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R is the distance between the sun and the Earth.

Substituting values, we have

F = \frac{6.67*10^{-11}*2*10^{30}*6*10^{24}}{(1.5*10^{11})^2} = <em>3.56 x 10^22 N</em>

<em></em>

A) The force exerted by the sun on the Earth is equal to the force exerted by the Earth on the Sun also, and the force is equal to <em>3.56 x 10^22 N</em>

b) The force exerted by the Earth on the Sun = <em>3.56 x 10^22 N</em>

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